{"id":1379,"date":"2021-01-15T08:04:00","date_gmt":"2021-01-15T08:04:00","guid":{"rendered":"http:\/\/worm-reducers.xyz\/?p=1379"},"modified":"2022-12-29T01:53:08","modified_gmt":"2022-12-29T01:53:08","slug":"conveyor-chain-selection","status":"publish","type":"post","link":"https:\/\/worm-reducers.xyz\/tr\/conveyor-chain-selection\/","title":{"rendered":"Konvey\u00f6r Zinciri Se\u00e7imi"},"content":{"rendered":"

girii\u015f
Konvey\u00f6r \u00e7evresindeki rahats\u0131zl\u0131klar\u0131n dikkatli bir \u015fekilde de\u011ferlendirilmesi, do\u011fru konvey\u00f6r zinciri se\u00e7imi i\u00e7in \u00f6nemlidir. Bu b\u00f6l\u00fcmde, ba\u015far\u0131l\u0131 bir konvey\u00f6r zinciri se\u00e7imi i\u00e7in gerekli temel hususlar ele al\u0131nmaktad\u0131r. Makaral\u0131 zincirler, genellikle hafif ila orta a\u011f\u0131rl\u0131ktaki malzeme ta\u015f\u0131ma uygulamalar\u0131nda kullan\u0131l\u0131r. \u00c7evresel ko\u015fullar, \u00f6zel bile\u015fenlerin, kaplamalar\u0131n, ya\u011flay\u0131c\u0131lar\u0131n kullan\u0131m\u0131n\u0131 veya hatta ek harici ya\u011flama olmadan \u00e7al\u0131\u015fma yetene\u011fini gerektirebilir.
Zincir \u00c7e\u015fitleri \u0130\u00e7in Gerekli Temel Bilgiler
Zincir konvey\u00f6r\u00fcn\u00fcn tipi (\u00fcnite veya toplu), ta\u015f\u0131ma sistemi (ek par\u00e7alar, kovalar, ara \u00e7ubuklar vb.) dahil.
Konvey\u00f6r d\u00fczeni, di\u015fli \u00e7ark yerleri, e\u011fimler (varsa) ve kullan\u0131lacak zincir teli say\u0131s\u0131 (N) gibi unsurlar\u0131 i\u00e7ermelidir.
Ta\u015f\u0131nacak malzemenin miktar\u0131 (M, lbs\/ft veya kN\/m cinsinden) ve t\u00fcr\u00fc.
Konvey\u00f6r par\u00e7alar\u0131n\u0131n (zincir, \u00e7\u0131talar veya varsa ek par\u00e7alar dahil) tahmini s\u00fcrt\u00fcnme kuvveti (W, lbs\/ft veya kN\/m cinsinden).
Do\u011frusal zincir h\u0131z\u0131 (S, ft\/dak veya m\/dak cinsinden).
Zincirin \u00e7al\u0131\u015faca\u011f\u0131 ortam; s\u0131cakl\u0131k, korozyon ko\u015fullar\u0131, ya\u011flama durumu vb. fakt\u00f6rleri i\u00e7erir.
Ad\u0131m 1: Zincir Gerilimini Tahmin Etme
Konvey\u00f6r \u00e7ekme kuvvetini (Pest) ve ard\u0131ndan zincir gerilimini (Test) tahmin etmek i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullan\u0131n. Pest = (M + W) xfx SF ve
Test = Ha\u015fere \/ N
f = S\u00fcrt\u00fcnme Katsay\u0131s\u0131
SF = H\u0131z Fakt\u00f6r\u00fc
\u0130kinci a\u015fama: Ge\u00e7ici bir zincir se\u00e7imi yap\u0131n
Kontrol de\u011ferini uygulayarak, bir zincir se\u00e7erek ge\u00e7ici bir \u00fcr\u00fcn yelpazesi olu\u015fturun.
Hesaplanan kontrol de\u011ferine k\u0131yasla daha y\u00fcksek i\u015f y\u00fck\u00fc kapasitesine sahip olanlar. Bu de\u011ferler konvey\u00f6r servisi i\u00e7in uygundur ve katalogun \u00f6n taraf\u0131ndaki tablolarda g\u00f6sterilen ve d\u00fc\u015f\u00fck h\u0131zl\u0131 tahrik zinciri kullan\u0131m\u0131na ba\u011fl\u0131 olan de\u011ferlerden farkl\u0131d\u0131r.
Yeterli y\u00fck ta\u015f\u0131ma kapasitesine ek olarak, bu zincirlerin genellikle istenen ba\u011flant\u0131 aral\u0131\u011f\u0131na uyacak \u015fekilde belirli bir ad\u0131m aral\u0131\u011f\u0131na sahip olmas\u0131 gerekir. \u00d6rne\u011fin, \u00e7\u0131talar her 1,5 in\u00e7te bir ba\u011flant\u0131ya c\u0131vatalanacaksa, se\u00e7ilen zincirin ad\u0131m aral\u0131\u011f\u0131 1,5'e b\u00f6l\u00fcnmelidir. Bu nedenle, her 3'te bir ba\u011flant\u0131 kullanarak 40'l\u0131k bir zincir (1\/2' ad\u0131m), her 2'de bir ba\u011flant\u0131 kullanarak 60'l\u0131k bir zincir (3\/4' ad\u0131m), her ad\u0131mda ba\u011flant\u0131 kullanarak 120'lik bir zincir (1-1\/2' ad\u0131m) veya her ad\u0131mda ba\u011flant\u0131 kullanarak C2060H zincir (1-1\/2' ad\u0131m) kullan\u0131labilir.
\u00dc\u00e7\u00fcnc\u00fc a\u015fama: Se\u00e7imi kesinle\u015ftirme \u2013 Ger\u00e7ek konvey\u00f6r \u00e7ekme kuvvetini belirleme
Ge\u00e7ici bir \u00fcr\u00fcn yelpazesi olu\u015fturduktan hemen sonra, bunu hesaplayarak do\u011frulamam\u0131z gerekiyor.
Ger\u00e7ek zincir gerilimi (T). Bunu tamamlamak i\u00e7in \u00f6ncelikle ger\u00e7ek konvey\u00f6r \u00e7ekme kuvvetini (P) hesaplamam\u0131z gerekiyor. Bu sayfan\u0131n uygun taraf\u0131nda g\u00f6sterilen d\u00fczenlerinizden uygun form\u00fcl\u00fc se\u00e7in ve toplam konvey\u00f6r \u00e7ekme kuvvetini hesaplay\u0131n. Baz\u0131 konvey\u00f6rlerin yatay, e\u011fimli ve dikeyin bir kar\u0131\u015f\u0131m\u0131 olabilece\u011fini unutmay\u0131n... bu durumda, her bir b\u00f6l\u00fcmdeki konvey\u00f6r \u00e7ekme kuvvetini belirleyin ve bunlar\u0131 toplay\u0131n.
D\u00f6rd\u00fcnc\u00fc a\u015fama: Optimum zincir gerilimini hesaplay\u0131n.
Maksimum Zincir Gerilimi (T), Faz 3'te hesaplanan Konvey\u00f6r \u00c7ekme Kuvveti (P)'nin, y\u00fck\u00fc ta\u015f\u0131yan tel say\u0131s\u0131na (N) b\u00f6l\u00fcnmesiyle elde edilir ve Tablo 2'de g\u00f6sterilen H\u0131z Bile\u015feni (SF) ve \u00c7oklu Tel Fakt\u00f6r\u00fc'n\u00fc i\u00e7erir. Tablo \u00fc\u00e7te kan\u0131tlanan (MSF) art\u0131 Tablo 4'te kan\u0131tlanan S\u0131cakl\u0131k Sorunu (TF).
T = (P \/ N) x MSF x SF x TF
Be\u015finci a\u015fama: Se\u00e7ilen zincirdeki \"Nominal \u00c7al\u0131\u015fma Y\u00fck\u00fc\"n\u00fc kontrol edin.
Se\u00e7ti\u011finiz zincirin \"Nominal \u00c7al\u0131\u015fma Y\u00fck\u00fc\", 4. a\u015famada hesaplanan Maksimum Zincir Gerilimi (T)'den daha y\u00fcksek olmal\u0131d\u0131r. Bu de\u011ferler konvey\u00f6r hizmeti i\u00e7in kabul edilebilir olup, bu nedenle katalogun \u00f6n taraf\u0131ndaki tablolarda d\u00fc\u015f\u00fck h\u0131zl\u0131 tahrik zinciri kullan\u0131m\u0131na ili\u015fkin g\u00f6sterilen de\u011ferlerden farkl\u0131d\u0131r.
Alt\u0131nc\u0131 ad\u0131m: Se\u00e7ilen zincirdeki \"\u0130zin Verilen Makaral\u0131 Y\u00fck\u00fc\" do\u011frulay\u0131n.
Zincir makaralar\u0131 \u00fczerinde veya \u00fcstten tak\u0131lan makara ba\u011flant\u0131 par\u00e7alar\u0131 \u00fczerinde d\u00f6nen zincirler i\u00e7in, izin verilen makara y\u00fck\u00fcn\u00fc kontrol etmek gerekebilir.
Not: Silindir y\u00fck\u00fc a\u015fa\u011f\u0131dakilere g\u00f6re belirlenir:
Silindir Y\u00fck\u00fc = Wr \/ Nr
Wr = Makaralar\u0131n ta\u015f\u0131d\u0131\u011f\u0131 toplam a\u011f\u0131rl\u0131k
Nr = Fazla a\u011f\u0131rl\u0131\u011f\u0131 destekleyen silindir say\u0131s\u0131.<\/p>","protected":false},"excerpt":{"rendered":"

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