{"id":1941,"date":"2026-04-17T05:04:15","date_gmt":"2026-04-17T05:04:15","guid":{"rendered":"https:\/\/worm-reducers.xyz\/?p=1941"},"modified":"2026-04-17T05:04:15","modified_gmt":"2026-04-17T05:04:15","slug":"worm-gear-reducer-torque-and-ratio-the-calculation-guide","status":"publish","type":"post","link":"https:\/\/worm-reducers.xyz\/sk\/worm-gear-reducer-torque-and-ratio-the-calculation-guide\/","title":{"rendered":"Kr\u00fatiaci moment a prevodov\u00fd pomer \u0161nekov\u00e9ho prevodu: Sprievodca v\u00fdpo\u010dtom"},"content":{"rendered":"
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Kr\u00fatiaci moment a prevodov\u00fd pomer \u0161nekov\u00e9ho prevodu: Sprievodca v\u00fdpo\u010dtom<\/h1>\n

Tabu\u013eky odpor\u00fa\u010dan\u00ed dod\u00e1vate\u013eov s\u00fa zostaven\u00e9 na z\u00e1klade priemernej aplik\u00e1cie. Va\u0161a aplik\u00e1cia m\u00e1 svoje \u0161pecifick\u00e9 za\u0165a\u017eenie, pracovn\u00fd cyklus, teplotu okolia a charakter n\u00e1razov. T\u00e1to pr\u00edru\u010dka v\u00e1s prevedie \u0161tyrmi z\u00e1kladn\u00fdmi vzorcami a tromi pracovn\u00fdmi pr\u00edkladmi, aby ste si mohli overi\u0165 ak\u00e9ko\u013evek z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod<\/strong> v\u00fdber za menej ako 20 min\u00fat.<\/p>\n

Z\u00edskajte podporu pre v\u00fdpo\u010dty<\/a><\/p>\n<\/div>\n<\/div>\n

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Pre\u010do by ste si mali v\u017edy po\u010d\u00edta\u0165 \u010d\u00edsla sami<\/h2>\n
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Tabu\u013eky odpor\u00fa\u010dan\u00ed dod\u00e1vate\u013eov s\u00fa vytvoren\u00e9 pre stredn\u00fa aplik\u00e1ciu \u2013 rovnomern\u00e9 za\u0165a\u017eenie, 8 hod\u00edn denne, okolit\u00e1 teplota 20 \u00b0C, minim\u00e1lne otrasy. V\u017edy, ke\u010f sa jedna z t\u00fdchto podmienok l\u00ed\u0161i od va\u0161ej skuto\u010dnej aplik\u00e1cie, odpor\u00fa\u010danie m\u00f4\u017ee by\u0165 nespr\u00e1vne. Nie nebezpe\u010dne nespr\u00e1vne, ale ticho nespr\u00e1vne sp\u00f4sobom, ktor\u00fd sp\u00f4sob\u00ed poruchu po 6 000 hodin\u00e1ch namiesto 20 000 hod\u00edn a nikto ju nikdy nesleduje sp\u00e4\u0165 k p\u00f4vodnej. z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod<\/strong> v\u00fdber.<\/p>\n

V\u00fdpo\u010det nie je zlo\u017eit\u00fd \u2013 s\u00fa to \u0161tyri vzorce, ktor\u00fdch vypo\u010d\u00edtanie trv\u00e1 15 min\u00fat pri prvej aplik\u00e1cii a 5 min\u00fat pri ka\u017edej nasleduj\u00facej aplik\u00e1cii. Samostatn\u00e9 vykonanie v\u00fdpo\u010dtov v\u00e1s tie\u017e n\u00fati presne definova\u0165 va\u0161u aplik\u00e1ciu: skuto\u010dn\u00fd v\u00fdstupn\u00fd kr\u00fatiaci moment, nie pribli\u017en\u00fd; skuto\u010dn\u00fd pracovn\u00fd cyklus, nie \u201epreru\u0161ovan\u00fd\u201c; skuto\u010dn\u00e1 teplota okolia, nie \u201eizbov\u00e1 teplota\u201c.<\/p>\n

Naj\u010dastej\u0161ie chyby pri dimenzovan\u00ed z\u00e1vitovkov\u00e9ho reduktora \u2013 poddimenzovan\u00fd prev\u00e1dzkov\u00fd faktor, ignorovan\u00fd limit tepeln\u00e9ho v\u00fdkonu, podhodnoten\u00e1 teplota okolia \u2013 s\u00fa v\u0161etky nevidite\u013en\u00e9 v tabu\u013eke odpor\u00fa\u010dan\u00ed a v\u0161etky vidite\u013en\u00e9 v 15-min\u00fatovom v\u00fdpo\u010dte.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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\u0160tyri z\u00e1kladn\u00e9 vzorce<\/h2>\n

Ka\u017ed\u00fd v\u00fdpo\u010det v\u00fdberu z\u00e1vitovkov\u00e9ho reduktora pou\u017e\u00edva tieto \u0161tyri vzorce. Na seba nadv\u00e4zuj\u00fa postupne \u2013 vypo\u010d\u00edtajte ich v porad\u00ed a m\u00e1te kompletn\u00fd z\u00e1klad pre v\u00fdber.<\/p>\n

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FORMULA 1<\/div>\n

Reduk\u010dn\u00fd pomer<\/h3>\n
i = n_vstup \u00f7 n_v\u00fdstup<\/div>\n

Kde:<\/strong> n_vstup = ot\u00e1\u010dky hriade\u013ea motora (ot\/min); n_v\u00fdstup = po\u017eadovan\u00e9 ot\u00e1\u010dky v\u00fdstupn\u00e9ho hriade\u013ea (ot\/min)<\/p>\n

Pr\u00edklad:<\/strong> Motor 1 450 ot.\/min, po\u017eadovan\u00fd v\u00fdkon 29 ot.\/min: i = 1 450 \u00f7 29 = 50:1<\/strong><\/p>\n

Praktick\u00e1 pozn\u00e1mka:<\/strong> \u0160tandardn\u00e9 prevodov\u00e9 pomery s\u00fa 5, 7,5, 10, 15, 20, 25, 30, 40, 50, 60, 80, 100. Ak sa v\u00e1\u0161 vypo\u010d\u00edtan\u00fd prevodov\u00fd pomer nach\u00e1dza medzi dvoma \u0161tandardn\u00fdmi hodnotami, v\u017edy ho zaokr\u00fahlite nahor na vy\u0161\u0161\u00ed prevodov\u00fd pomer (ni\u017e\u0161ia v\u00fdstupn\u00e1 r\u00fdchlos\u0165) \u2013 nikdy ho nezaokr\u00fah\u013eujte nadol.<\/p>\n<\/div>\n

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FORMULA 2<\/div>\n

V\u00fdstupn\u00fd kr\u00fatiaci moment (teoretick\u00fd)<\/h3>\n
T\u2082 = T\u2081 \u00d7 i \u00d7 \u03b7<\/div>\n

Kde:<\/strong> T\u2081 = kr\u00fatiaci moment na hriadeli motora (N\u00b7m); i = prevodov\u00fd pomer; \u03b7 = \u00fa\u010dinnos\u0165 pri tomto pomere (desatinne)<\/p>\n

D\u00f4le\u017eit\u00e9:<\/strong> \u00da\u010dinnos\u0165 \u03b7 nie je kon\u0161tantn\u00e1 \u2013 z\u00e1vis\u00ed od zvolen\u00e9ho pomeru. Pozri tabu\u013eku referen\u010dnej \u00fa\u010dinnosti v \u010dasti 4.<\/p>\n

Pr\u00edklad:<\/strong> T\u2081 = 4,0 N\u00b7m (motor), i = 50, \u03b7 = 0,60: T\u2082 = 4,0 \u00d7 50 \u00d7 0,60 = 120 N\u00b7m<\/strong><\/p>\n<\/div>\n

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FORMULA 3<\/div>\n

Po\u017eadovan\u00fd vstupn\u00fd v\u00fdkon<\/h3>\n
P_vstup = (T\u2082 \u00d7 n\u2082) \u00f7 (9 550 \u00d7 \u03b7)<\/div>\n

Jednotky:<\/strong> P_pr\u00edkon v kW; T\u2082 v N\u00b7m; n\u2082 v ot.\/min<\/p>\n

Kon\u0161tanta 9 550 prepo\u010d\u00edtava medzi rota\u010dnou a v\u00fdkonovou jednotkou. Toto je v\u00fdkon, ktor\u00fd mus\u00ed motor doda\u0165 \u2013 nie katal\u00f3gov\u00fd v\u00fdkon motora.<\/p>\n

Pr\u00edklad:<\/strong> T\u2082 = 120 N\u00b7m, n\u2082 = 29 ot.\/min, \u03b7 = 0,60: P_vstup = (120 \u00d7 29) \u00f7 (9 550 \u00d7 0,60) = 0,607 kW<\/strong><\/p>\n<\/div>\n

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FORMULA 4<\/div>\n

Korekcia faktora slu\u017eby<\/h3>\n
Po\u017eadovan\u00e1_T = Skuto\u010dn\u00e1_T \u00d7 SF<\/div>\n

Pred porovnan\u00edm s katal\u00f3gov\u00fdm menovit\u00fdm kr\u00fatiacim momentom aplikujte SF na skuto\u010dn\u00fd po\u017eadovan\u00fd v\u00fdstupn\u00fd kr\u00fatiaci moment. Katal\u00f3gov\u00fd T\u2082n mus\u00ed by\u0165 \u2265 T_required.<\/p>\n

Pr\u00edklad:<\/strong> T_skuto\u010dn\u00e1 = 120 N\u00b7m, SF = 1,5 (\u013eahk\u00fd \u0161ok, 8h\/de\u0148): T_po\u017eadovan\u00e1 = 120 \u00d7 1,5 = 180 N\u00b7m<\/strong><\/p>\n

Vyberte z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod s katal\u00f3gov\u00fdm T\u2082n \u2265 180 N\u00b7m pri prevodovom pomere 50:1.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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Sprievodca faktorom slu\u017eieb (SF): Naj\u010dastej\u0161ie podce\u0148ovan\u00fd parameter<\/h2>\n
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Servisn\u00fd faktor zoh\u013ead\u0148uje skuto\u010dn\u00e9 podmienky za\u0165a\u017eenia v porovnan\u00ed s katal\u00f3gov\u00fdmi testovac\u00edmi podmienkami. Katal\u00f3gov\u00e9 menovit\u00e9 hodnoty z\u00e1vitovkov\u00e9ho reduktora predpokladaj\u00fa rovnomern\u00e9 za\u0165a\u017eenie pri menovit\u00fdch ot\u00e1\u010dkach po\u010das trvania testu. Ka\u017ed\u00e1 odch\u00fdlka od tejto z\u00e1kladnej hodnoty zvy\u0161uje efekt\u00edvne za\u0165a\u017eenie ozuben\u00fdch kolies a lo\u017e\u00edsk. Servisn\u00fd faktor (SF) premie\u0148a va\u0161e skuto\u010dn\u00e9 prev\u00e1dzkov\u00e9 podmienky na ekvivalentn\u00fa po\u017eiadavku na v\u00fdber z katal\u00f3gu.<\/p>\n

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\n\n\n\n\n\n\n\n\n
Na\u010d\u00edta\u0165 znak<\/th>\n\u22642 h\/de\u0148<\/th>\n2\u201310 h\/de\u0148<\/th>\n>10 h\/de\u0148<\/th>\n<\/tr>\n<\/thead>\n
Rovnomern\u00e9 za\u0165a\u017eenie<\/td>\n1.00<\/td>\n1.25<\/td>\n1.50<\/td>\n<\/tr>\n
\u013dahk\u00fd \u0161ok<\/td>\n1.25<\/td>\n1.50<\/td>\n1.75<\/td>\n<\/tr>\n
Mierny \u0161ok<\/td>\n1.50<\/td>\n1.75<\/td>\n2.00<\/td>\n<\/tr>\n
Siln\u00fd \u0161ok<\/td>\n1.75<\/td>\n2.00<\/td>\n2.25<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

Typick\u00e9 pr\u00edklady zariaden\u00ed pod\u013ea kateg\u00f3rie tlmi\u010dov<\/h3>\n
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Uniforma:<\/strong> Odstrediv\u00e9 ventil\u00e1tory, odstrediv\u00e9 \u010derpadl\u00e1, \u013eahk\u00e9 dopravn\u00e9 p\u00e1sy (bez rozbehu pod za\u0165a\u017een\u00edm), baliace stroje pri kon\u0161tantnej r\u00fdchlosti.<\/div>\n
\u013dahk\u00fd \u0161ok:<\/strong> Dopravn\u00edky, ktor\u00e9 sa sp\u00fa\u0161\u0165aj\u00fa pod za\u0165a\u017een\u00edm, mie\u0161adl\u00e1 s kvapalinami s rovnomernou viskozitou, be\u017en\u00e9 tov\u00e1rensk\u00e9 stroje s ob\u010dasn\u00fdmi zmenami za\u0165a\u017eenia.<\/div>\n
Mierny \u0161ok:<\/strong> Kompresory, mie\u0161a\u010dky s variabiln\u00fdm d\u00e1vkovan\u00edm kalu, z\u00e1vitovkov\u00e9 dopravn\u00edky, navijaky, kore\u010dkov\u00e9 elev\u00e1tory, sitov\u00e9 pod\u00e1va\u010de.<\/div>\n
Siln\u00fd \u0161ok:<\/strong> Vibra\u010dn\u00e9 pod\u00e1va\u010de, \u010de\u013eus\u0165ov\u00e9 drvi\u010de, zariadenia na triedenie r\u00fad, kladivov\u00e9 mlyny, pomocn\u00e9 zariadenia na v\u0155tanie horn\u00edn.<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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\u00da\u010dinnos\u0165 vs. pomer: Referen\u010dn\u00e9 \u00fadaje, ktor\u00e9 potrebujete pre ka\u017ed\u00fd v\u00fdpo\u010det<\/h2>\n
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\u00da\u010dinnos\u0165 z\u00e1vitovkov\u00e9ho reduktora nie je jedna pevn\u00e1 hodnota \u2013 v\u00fdrazne sa men\u00ed v z\u00e1vislosti od reduk\u010dn\u00e9ho pomeru. Pou\u017eitie nespr\u00e1vnej hodnoty \u00fa\u010dinnosti vo v\u00fdpo\u010dte vedie k nespr\u00e1vnemu vstupn\u00e9mu v\u00fdkonu a nespr\u00e1vnym odhadom kr\u00fatiaceho momentu. Nasleduj\u00faca tabu\u013eka uv\u00e1dza realistick\u00e9 rozsahy pre z\u00e1vitovkov\u00e9 reduktory s\u00e9rie WP a NMRV s pou\u017eit\u00edm \u0161tandardn\u00e9ho miner\u00e1lneho oleja ISO VG 220 pri prev\u00e1dzkovej teplote.<\/p>\n

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\n\n\n\n\n\n\n\n\n\n\n\n\n
Pomer (i)<\/th>\n\u00da\u010dinnos\u0165 \u03b7 Rozsah<\/th>\nPou\u017eitie vo v\u00fdpo\u010dte<\/th>\n<\/tr>\n<\/thead>\n
7.5:1<\/td>\n85\u201390%<\/td>\n\u03b7 = 0,87<\/td>\n<\/tr>\n
10:1<\/td>\n80\u201385%<\/td>\n\u03b7 = 0,82<\/td>\n<\/tr>\n
20:1<\/td>\n70\u201378%<\/td>\n\u03b7 = 0,74<\/td>\n<\/tr>\n
30:1<\/td>\n65\u201373%<\/td>\n\u03b7 = 0,69<\/td>\n<\/tr>\n
40:1<\/td>\n60\u201368%<\/td>\n\u03b7 = 0,64<\/td>\n<\/tr>\n
50:1<\/td>\n55\u201364%<\/td>\n\u03b7 = 0,60<\/td>\n<\/tr>\n
60:1<\/td>\n50\u201358%<\/td>\n\u03b7 = 0,54<\/td>\n<\/tr>\n
80 \u2013 100:1<\/td>\n44\u201355%<\/td>\n\u03b7 = 0,49<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

Horn\u00e1 hranica rozsahu: koleso z vysokoc\u00ednov\u00e9ho bronzu (10%+ Sn), presne br\u00fasen\u00fd z\u00e1vitovkov\u00fd hriade\u013e, syntetick\u00fd olej PAO. Doln\u00e1 hranica: \u0161tandardn\u00fd bronz, rezan\u00fd z\u00e1vitovkov\u00fd hriade\u013e, miner\u00e1lny olej. Pre konzervat\u00edvne dimenzovanie pou\u017eite doln\u00fa hodnotu rozsahu.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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Tri kompletn\u00e9 spracovan\u00e9 pr\u00edklady<\/h2>\n

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Pr\u00edklad 1: Pohon dopravn\u00edka (rovnomern\u00e9 za\u0165a\u017eenie, 8 h\/de\u0148)<\/h3>\n
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Vzh\u013eadom na:<\/strong> P\u00e1sov\u00fd dopravn\u00edk. R\u00fdchlos\u0165 p\u00e1su 1,2 m\/s. Priemer hnacieho bubna 300 mm. Hmotnos\u0165 za\u0165a\u017een\u00e9ho p\u00e1su 800 kg. Koeficient trenia \u03bc = 0,05. Prev\u00e1dzka 8 hod\u00edn denne, rovnomern\u00e9 za\u0165a\u017eenie.<\/p>\n

Krok 1 \u2013 Po\u017eadovan\u00e9 ot\u00e1\u010dky bubna:<\/strong>
\nn_bubon = (v \u00d7 60) \/ (\u03c0 \u00d7 D) = (1,2 \u00d7 60) \/ (\u03c0 \u00d7 0,30) = 76 ot.\/min.<\/p>\n

Krok 2 \u2013 Sila a kr\u00fatiaci moment pohonu reme\u0148a:<\/strong>
\nF = m \u00d7 g \u00d7 \u03bc = 800 \u00d7 9,81 \u00d7 0,05 = 392 N
\nT_bubna = F \u00d7 r = 392 \u00d7 0,15 = 58,8 N\u00b7m<\/strong><\/p>\n

Krok 3 \u2013 Pomer:<\/strong>
\ni = 1 450 \/ 76 = 19,1 \u2192 vyberte 20:1<\/strong><\/p>\n<\/div>\n

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Krok 4 \u2013 Aplik\u00e1cia SF:<\/strong>
\nSF = 1,25 (rovnomern\u00e9 za\u0165a\u017eenie, 8 h\/de\u0148)
\nPo\u017eadovan\u00e1_T = 58,8 \u00d7 1,25 = 73,5 N\u00b7m<\/strong><\/p>\n

Krok 5 \u2013 Overenie vstupn\u00e9ho nap\u00e1jania:<\/strong>
\n\u03b7 pri 20:1 = 0,74
\nP_vstup = (58,8 \u00d7 76) \/ (9 550 \u00d7 0,74) = 0,63 kW<\/strong><\/p>\n

Krok 6 \u2013 Tepeln\u00e1 kontrola:<\/strong>
\nTrval\u00e1 prev\u00e1dzka pri 20 \u00b0C: P_th pre NMRV-050 pri 20:1 = pribli\u017ene 3,2 kW \u226b 0,63 kW. Tepeln\u00e1 rezerva je dostato\u010dn\u00e1.<\/p>\n

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\u2713 Vybran\u00e9: NMRV-050 pri 20:1<\/strong>
\nKatal\u00f3g T\u2082n \u2265 73,5 N\u00b7m pri 20:1. Motor: 0,75 kW (\u010fal\u0161ia \u0161tandardn\u00e1 ve\u013ekos\u0165 nad 0,63 kW).<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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Pr\u00edklad 2: Pohon mie\u0161adla (mierny \u0161ok, 16 h\/de\u0148)<\/h3>\n
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Vzh\u013eadom na:<\/strong> Priemyseln\u00e9 mie\u0161adlo kalu. Po\u017eadovan\u00fd v\u00fdstupn\u00fd kr\u00fatiaci moment 320 N\u00b7m pri 28 ot.\/min. Prev\u00e1dzka 16 hod\u00edn denne, mierne r\u00e1zy (premenliv\u00e1 hustota kalu). Okolit\u00e1 teplota 30 \u00b0C. Otvoren\u00e1 in\u0161tal\u00e1cia.<\/p>\n

Krok 1 \u2013 Pomer:<\/strong>
\ni = 1 450 \/ 28 = 51,8 \u2192 vyberte 50:1<\/strong>
\n(Skuto\u010dn\u00e9 v\u00fdstupn\u00e9 ot\u00e1\u010dky = 1 450 \/ 50 = 29 ot.\/min. \u2013 prijate\u013en\u00e9)<\/p>\n

Krok 2 \u2013 Aplik\u00e1cia SF:<\/strong>
\nSF = 2,00 (mierny \u0161ok, >10 h\/de\u0148)
\nPo\u017eadovan\u00e1_T = 320 \u00d7 2,00 = 640 N\u00b7m<\/strong><\/p>\n<\/div>\n

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Krok 3 \u2013 Vstupn\u00fd v\u00fdkon:<\/strong>
\n\u03b7 pri 50:1 = 0,60
\nP_vstup = (320 \u00d7 28) \/ (9 550 \u00d7 0,60) = 1,56 kW<\/strong><\/p>\n

Krok 4 \u2013 Tepeln\u00e1 kontrola pri 30 \u00b0C:<\/strong>
\nFaktor okolia pri 30 \u00b0C = 0,87
\nNMRV-090 pri 50:1 P_th katal\u00f3g = 4,8 kW
\nKorigovan\u00fd P_th = 4,8 \u00d7 0,87 = 4,18 kW \u226b 1,56 kW. \u2713<\/p>\n

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\u2713 Vybran\u00e9: NMRV-090 pri 50:1<\/strong>
\nT\u2082n pri 50:1 mus\u00ed by\u0165 \u2265 640 N\u00b7m. Potvr\u010fte v katal\u00f3gu. Motor: 2,2 kW.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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Pr\u00edklad 3: Pomocn\u00fd pohon zdv\u00edhacieho zariadenia (siln\u00e9 r\u00e1zy, preru\u0161ovan\u00e9)<\/h3>\n
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Vzh\u013eadom na:<\/strong> Pohon bubna pomocn\u00e9ho zdv\u00edhacieho zariadenia. Zdv\u00edhacia hmotnos\u0165 1 200 kg. R\u00fdchlos\u0165 zdvihu 0,4 m\/s. Priemer bubna 400 mm. Pracovn\u00fd cyklus: 15 sek\u00fand zapnut\u00e9, 45 sek\u00fand vypnut\u00e9. Vy\u017eaduje sa samosvorn\u00e9 uzamknutie.<\/p>\n

Krok 1 \u2013 Kr\u00fatiaci moment bubna:<\/strong>
\nF = 1 200 \u00d7 9,81 = 11 772 N
\nT_bubna = F \u00d7 r = 11 772 \u00d7 0,20 = 2 354 N\u00b7m<\/strong><\/p>\n

Krok 2 \u2013 Ot\u00e1\u010dky bubna:<\/strong>
\nn_bubon = (0,4 \u00d7 60) \/ (\u03c0 \u00d7 0,40) = 19,1 ot.\/min.
\nPomer: i = 1,450 \/ 19,1 = 75,9 \u2192 80:1<\/strong> (potvrden\u00e9 samosvorn\u00e9 uzamknutie)<\/p>\n<\/div>\n

\n

Krok 3 \u2013 \u00da\u010dinn\u00fd v\u00fdkon po\u010das pracovn\u00e9ho cyklu:<\/strong>
\nDC = 15\/(15+45) = 25%
\nP_eff = P_peak \u00d7 \u221a(DC) = P_peak \u00d7 0,50<\/p>\n

Krok 4 \u2013 Aplik\u00e1cia SF:<\/strong>
\nSF = 1,75 (siln\u00fd \u0161ok, ekvivalent \u22642 h\/de\u0148)
\nPo\u017eadovan\u00e1_T = 2 354 \u00d7 1,75 = 4 120 N\u00b7m<\/strong><\/p>\n

Vrchol vstupu P:<\/strong> \u03b7 pri 80:1 = 0,50
\nP_peak = (2 354 \u00d7 19,1) \/ (9 550 \u00d7 0,50) = 9,43 kW<\/strong><\/p>\n

\n

\u2713 Vybran\u00e9: WP135 pri 80:1<\/strong>
\nT\u2082n \u2265 4 120 N\u00b7m. Motor: 11 kW. Tepeln\u00e1 kontrola: P_eff = 9,43 \u00d7 0,50 = 4,7 kW \u2013 overte P_th pre WP135 pri 80:1 pri skuto\u010dnej okolitej teplote.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

<\/p>\n

\n

Overenie tepeln\u00e9ho v\u00fdkonu: Kontrola, ktor\u00e1 zabra\u0148uje poruch\u00e1m sp\u00f4soben\u00fdm prehriat\u00edm<\/h2>\n
\n
\n

Pre ak\u00fako\u013evek aplik\u00e1ciu s nepretr\u017eitou prev\u00e1dzkou (S1 alebo pracovn\u00fd cyklus >50%) je overenie tepeln\u00e9ho v\u00fdkonu povinn\u00fdm dodato\u010dn\u00fdm krokom po v\u00fdpo\u010dte kr\u00fatiaceho momentu\/prevodov\u00e9ho pomeru. Mnoho spr\u00e1vne dimenzovan\u00fdch z\u00e1vitovkov\u00fdch reduktorov \u2013 s potvrden\u00fdm kr\u00fatiacim momentom a prevodov\u00fdm pomerom \u2013 zlyhalo, preto\u017ee limit tepeln\u00e9ho v\u00fdkonu nebol nikdy skontrolovan\u00fd.<\/p>\n

<\/p>\n

Postup tepeln\u00e9ho overovania:<\/strong><\/p>\n

1.<\/strong> Z v\u00fdpo\u010dtu zaznamenajte skuto\u010dn\u00fd trval\u00fd vstupn\u00fd v\u00fdkon P_input (kW).<\/p>\n

2.<\/strong> Z vybran\u00e9ho katal\u00f3gu z\u00e1vitovkov\u00fdch reduk\u010dn\u00fdch prevodov n\u00e1jdite P_th pri zvolenom prevodovom pomere.<\/p>\n

3.<\/strong> Pou\u017eite korek\u010dn\u00fd faktor teploty okolia (\u00fapln\u00fa tabu\u013eku n\u00e1jdete v \u010dl\u00e1nku K-05).<\/p>\n

4.<\/strong> Ak je prilo\u017een\u00e1, pou\u017eite korekciu in\u0161tal\u00e1cie (odpo\u010d\u00edtajte 15\u201325%).<\/p>\n

5.<\/strong> Potvr\u010fte, \u017ee P_input < P_th (opraven\u00e9). Ak nie, prejdite na \u010fal\u0161iu ve\u013ekos\u0165 r\u00e1mu alebo pridajte chladenie.<\/p>\n

\n

K\u00f3rejsk\u00e1 letn\u00e1 pozn\u00e1mka:<\/strong> Pri teplote okolia 35 \u00b0C je korigovan\u00e1 hodnota P_th pribli\u017ene 801 TP3T katal\u00f3govej hodnoty. Z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod vybran\u00fd v katal\u00f3gu P_th bez korekcie teploty okolia bude v tepl\u00fdch letn\u00fdch d\u0148och be\u017ea\u0165 nad svoj tepeln\u00fd limit \u2013 aj ke\u010f v zime be\u017e\u00ed bez probl\u00e9mov. V\u017edy aplikujte korekciu teploty okolia.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

<\/p>\n

\n

\u0160tyri chyby vo v\u00fdpo\u010dtoch, ktor\u00e9 sa objavuj\u00fa naj\u010dastej\u0161ie<\/h2>\n
\n
\n

Chyba 1: Pou\u017eitie nap\u00e1jania z typov\u00e9ho \u0161t\u00edtku motora ako nap\u00e1jania aplik\u00e1cie<\/h3>\n

Motor s v\u00fdkonom 2,2 kW, ktor\u00fd poh\u00e1\u0148a \u013eahko za\u0165a\u017een\u00fd dopravn\u00edk, m\u00f4\u017ee za skuto\u010dn\u00fdch prev\u00e1dzkov\u00fdch podmienok doda\u0165 na hriadeli iba 0,8 kW. Pou\u017eitie 2,2 kW vo v\u00fdpo\u010dte nadhodnocuje vstupn\u00fd v\u00fdkon o 175%, \u010do vedie k \u00fadaju o vstupnom v\u00fdkone, ktor\u00fd sp\u00f4sobuje, \u017ee tepeln\u00e1 kontrola vyzer\u00e1 hor\u0161ie ako realita.<\/p>\n

Spr\u00e1vny pr\u00edstup:<\/strong> Vypo\u010d\u00edtajte skuto\u010dn\u00fd po\u017eadovan\u00fd vstupn\u00fd v\u00fdkon z parametrov za\u0165a\u017eenia (vzorce 2 a 3). Typov\u00fd \u0161t\u00edtok motora pou\u017eite iba na potvrdenie, \u017ee motor je dostato\u010dne ve\u013ek\u00fd \u2013 nie ako vstupn\u00fd v\u00fdkon pre tepeln\u00e9 pos\u00fadenie.<\/p>\n<\/div>\n

\n

Chyba 2: Priame porovnanie skuto\u010dn\u00e9ho kr\u00fatiaceho momentu s katal\u00f3gov\u00fdm T\u2082n bez SF<\/h3>\n

Katal\u00f3gov\u00e1 hodnota T\u2082n je hodnotenie testovac\u00edch podmienok. Kr\u00fatiaci moment aplik\u00e1cie vyn\u00e1soben\u00fd SF je hodnota, ktor\u00e1 mus\u00ed by\u0165 ni\u017e\u0161ia ako T\u2082n. Presko\u010denie SF znamen\u00e1 v\u00fdber z\u00e1vitovkov\u00e9ho reduk\u010dn\u00e9ho prevodu, ktor\u00fd sp\u013a\u0148a priemern\u00fd po\u017eadovan\u00fd kr\u00fatiaci moment, ale zlyh\u00e1 pri \u0161pi\u010dkovom za\u0165a\u017een\u00ed, ktor\u00e9 sa vyskytuje desiatky kr\u00e1t za prev\u00e1dzkov\u00fd cyklus.<\/p>\n

Spr\u00e1vny pr\u00edstup:<\/strong> Pred pre\u010d\u00edtan\u00edm katal\u00f3gu v\u017edy vypo\u010d\u00edtajte T_required = T_actual \u00d7 SF. Nikdy neporovn\u00e1vajte surov\u00fd aplika\u010dn\u00fd kr\u00fatiaci moment s T\u2082n.<\/p>\n<\/div>\n

\n

Chyba 3: Pou\u017eitie katal\u00f3govej \u00fa\u010dinnosti pre tepeln\u00e9 v\u00fdpo\u010dty<\/h3>\n

Hodnoty \u00fa\u010dinnosti z katal\u00f3gu predstavuj\u00fa najlep\u0161\u00ed pr\u00edpad \u2013 pln\u00e9 za\u0165a\u017eenie, prev\u00e1dzkov\u00e1 teplota, presne br\u00fasen\u00fd z\u00e1vitovkov\u00fd mechanizmus, vysokokvalitn\u00fd olej. Pri \u010diasto\u010dnom za\u0165a\u017een\u00ed, studenom \u0161tarte alebo so \u0161tandardn\u00fdmi komponentmi je \u00fa\u010dinnos\u0165 ni\u017e\u0161ia \u2013 \u010do znamen\u00e1, \u017ee sa vytv\u00e1ra viac tepla v porovnan\u00ed s v\u00fdstupn\u00fdm v\u00fdkonom.<\/p>\n

Spr\u00e1vny pr\u00edstup:<\/strong> Pri v\u00fdpo\u010dtoch tepeln\u00e9ho v\u00fdkonu pou\u017eite doln\u00fa hranicu rozsahu \u00fa\u010dinnosti (konzervat\u00edvnu hodnotu), nie katal\u00f3gov\u00fa \u0161pi\u010dkov\u00fa hodnotu. Vo v\u00fdpo\u010dte sa m\u00fdlite na stranu generovania v\u00e4\u010d\u0161ieho mno\u017estva tepla.<\/p>\n<\/div>\n

\n

Chyba 4: Ignorovanie teploty okolia pri tepelnej kontrole<\/h3>\n

Tepeln\u00fd v\u00fdkon P_th ka\u017ed\u00e9ho z\u00e1vitovkov\u00e9ho reduktora je uveden\u00fd v katal\u00f3gu pri okolitej teplote 20 \u00b0C. V k\u00f3rejskom priemyselnom prostred\u00ed je norm\u00e1lna letn\u00e1 okolit\u00e1 teplota 30 \u2013 35 \u00b0C. Pri 35 \u00b0C klesne P_th na 80% katal\u00f3govej hodnoty \u2013 \u010do je rozdiel, ktor\u00fd zmen\u00ed \u201e\u00faspe\u0161n\u00fa\u201c tepeln\u00fa kontrolu na \u201ene\u00faspe\u0161n\u00fa\u201c.<\/p>\n

Spr\u00e1vny pr\u00edstup:<\/strong> Pred porovnan\u00edm so skuto\u010dn\u00fdm vstupn\u00fdm v\u00fdkonom v\u017edy pou\u017eite korek\u010dn\u00fd faktor teploty okolia na P_th. Pou\u017eite najteplej\u0161iu o\u010dak\u00e1van\u00fa teplotu okolia pre dan\u00e9 miesto in\u0161tal\u00e1cie.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

<\/p>\n

<\/div>\n

<\/p>\n

\n

\u010casto kladen\u00e9 ot\u00e1zky \u2013 V\u00fdpo\u010dty kr\u00fatiaceho momentu a prevodov\u00e9ho pomeru z\u00e1vitovkov\u00e9ho prevodu<\/h2>\n
\nAk\u00fd ve\u013ek\u00fd v\u00fdznam m\u00e1, ak presn\u00fd vypo\u010d\u00edtan\u00fd pomer (napr. 47,2:1) nezodpoved\u00e1 \u0161tandardn\u00e9mu pomeru (50:1)?<\/summary>\n
\u0160tandardn\u00e9 prevodov\u00e9 pomery z\u00e1vitovkov\u00fdch reduk\u010dn\u00fdch prevodov s\u00fa nomin\u00e1lne uveden\u00e9 hodnoty s toleranciou pribli\u017ene \u00b13%. Z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod 50:1 teda m\u00f4\u017ee v praxi v skuto\u010dnosti poskytova\u0165 48,5:1 a\u017e 51,5:1 v z\u00e1vislosti od skuto\u010dn\u00e9ho po\u010dtu zubov konkr\u00e9tnej jednotky. Ak je v\u00e1\u0161 vypo\u010d\u00edtan\u00fd po\u017eadovan\u00fd pomer 47,2:1, v\u00fdberom jednotky 50:1 z\u00edskate ni\u017e\u0161iu v\u00fdstupn\u00fa r\u00fdchlos\u0165, ako je vypo\u010d\u00edtan\u00e1 \u2013 vo v\u00e4\u010d\u0161ine aplik\u00e1ci\u00ed dopravn\u00edkov a mie\u0161adiel je to prijate\u013en\u00e9. Ak je v\u00fdstupn\u00e1 r\u00fdchlos\u0165 pr\u00edsne regulovan\u00e1 (napr. synchroniza\u010dn\u00fd pohon), pou\u017eite na \u00fapravu ot\u00e1\u010dok motora frekven\u010dn\u00fd meni\u010d, aby ste kompenzovali odch\u00fdlku pomeru. Nikdy nevyberajte prevodov\u00fd pomer ni\u017e\u0161\u00ed ako je vypo\u010d\u00edtan\u00e1 hodnota \u2013 v takom pr\u00edpade bud\u00fa v\u00fdstupn\u00e9 ot\u00e1\u010dky vy\u0161\u0161ie, ako je \u0161pecifikovan\u00e9.<\/div>\n<\/details>\n
\nAko vypo\u010d\u00edtam skuto\u010dn\u00fd v\u00fdstupn\u00fd kr\u00fatiaci moment z \u00fadajov na typovom \u0161t\u00edtku m\u00f4jho motora?<\/summary>\n
Z typov\u00e9ho \u0161t\u00edtku motora: T_motora (N\u00b7m) = (P_typov\u00fd \u0161t\u00edtok \u00d7 9 550) \/ n_motora. Motor s v\u00fdkonom 1,5 kW pri 1 450 ot.\/min. vytv\u00e1ra na hriadeli motora T_motora = (1,5 \u00d7 9 550) \/ 1 450 = 9,88 N\u00b7m. Toto je v\u0161ak menovit\u00fd trval\u00fd kr\u00fatiaci moment motora \u2013 skuto\u010dn\u00fd dod\u00e1van\u00fd kr\u00fatiaci moment z\u00e1vis\u00ed od mechanick\u00e9ho za\u0165a\u017eenia. Ak za\u0165a\u017eenie vy\u017eaduje iba 50% kapacity motora, motor dod\u00e1va 4,94 N\u00b7m. Pri dimenzovan\u00ed z\u00e1vitovkov\u00e9ho reduk\u010dn\u00e9ho prevodu v\u017edy vypo\u010d\u00edtajte po\u017eadovan\u00fd kr\u00fatiaci moment zo za\u0165a\u017eenia (sila za\u0165a\u017eenia \u00d7 rameno momentu) a potom dimenzujte motor na z\u00e1klade tejto po\u017eiadavky \u2013 nie naopak.<\/div>\n<\/details>\n
\nKe\u010f sa pou\u017eije meni\u010d s frekvenciou (VFD), ako sa zmen\u00ed v\u00fdpo\u010det kr\u00fatiaceho momentu a prevodov\u00e9ho pomeru?<\/summary>\n
Meni\u010d frekvencie (VFD) men\u00ed ot\u00e1\u010dky motora, ale nie kr\u00fatiaci moment motora pri danej frekvencii. V\u00fdber z\u00e1vitovkov\u00e9ho reduktora sa st\u00e1le riadi rovnak\u00fdmi \u0161tyrmi vzorcami \u2013 v\u00fdpo\u010det z kr\u00fatiaceho momentu z\u00e1\u0165a\u017ee a po\u017eadovan\u00fdch v\u00fdstupn\u00fdch ot\u00e1\u010dok, ur\u010denie prevodov\u00e9ho pomeru z v\u00fdstupn\u00fdch ot\u00e1\u010dok a maxim\u00e1lnych ot\u00e1\u010dok motora. Meni\u010d frekvencie (VFD) potom umo\u017e\u0148uje meni\u0165 ot\u00e1\u010dky motora v r\u00e1mci prevodov\u00e9ho pomeru, \u010d\u00edm zabezpe\u010duje jemn\u00fa regul\u00e1ciu ot\u00e1\u010dok. D\u00f4le\u017eit\u00e9 obmedzenie: pri frekvenci\u00e1ch VFD pod 30 Hz je \u00fa\u010dinnos\u0165 chladiaceho ventil\u00e1tora motora v \u0161tandardn\u00fdch asynchr\u00f3nnych motoroch zn\u00ed\u017een\u00e1 (ventil\u00e1tor je namontovan\u00fd na hriadeli). Pri zn\u00ed\u017een\u00fdch ot\u00e1\u010dkach m\u00f4\u017ee by\u0165 potrebn\u00e9 zn\u00ed\u017ei\u0165 v\u00fdkon motora alebo pou\u017ei\u0165 samostatne nap\u00e1jan\u00fd chladiaci ventil\u00e1tor. Taktie\u017e pri ve\u013emi n\u00edzkej frekvencii VFD (pod 10 Hz) nemus\u00ed by\u0165 mazivo z\u00e1vitovkov\u00e9ho reduktora dostato\u010dne premie\u0161an\u00e9 \u2013 overte si minim\u00e1lne odpor\u00fa\u010dan\u00e9 ot\u00e1\u010dky vstupn\u00e9ho hriade\u013ea u dod\u00e1vate\u013ea z\u00e1vitovkov\u00e9ho reduktora.<\/div>\n<\/details>\n
\nAko sa vypo\u010d\u00edta celkov\u00e1 \u00fa\u010dinnos\u0165 dvojstup\u0148ov\u00e9ho z\u00e1vitovkov\u00e9ho reduk\u010dn\u00e9ho prevodu?<\/summary>\n
Pre dva stupne z\u00e1vitovkov\u00e9ho prevodu zapojen\u00e9 s\u00e9riovo je celkov\u00e1 \u00fa\u010dinnos\u0165 s\u00fa\u010dinom \u00fa\u010dinnost\u00ed jednotliv\u00fdch stup\u0148ov: \u03b7_total = \u03b7_stage1 \u00d7 \u03b7_stage2. Dva stupne s \u03b7 = 0,65 produkuj\u00fa \u03b7_total = 0,65 \u00d7 0,65 = 0,42 \u2013 celkov\u00e1 \u00fa\u010dinnos\u0165 je iba 42%. Preto sa dvojstup\u0148ov\u00e9 z\u00e1vitovkov\u00e9 usporiadania pou\u017e\u00edvaj\u00fa iba vtedy, ke\u010f \u017eiadny jednostup\u0148ov\u00fd z\u00e1vitovkov\u00fd prevod nedok\u00e1\u017ee dosiahnu\u0165 po\u017eadovan\u00fd prevodov\u00fd pomer (nad 100:1), a aj vtedy m\u00f4\u017ee by\u0165 jeden z\u00e1vitovkov\u00fd stupe\u0148 v kombin\u00e1cii s rovnobe\u017en\u00fdm \u0161pir\u00e1lov\u00fdm stup\u0148om \u00fa\u010dinnej\u0161ou alternat\u00edvou. Kontakt K\u00f3rea Ever-Power<\/a> pre vedenie viacstup\u0148ov\u00e9ho usporiadania pohonu.<\/div>\n<\/details>\n
\nAk sa skuto\u010dn\u00e9 za\u0165a\u017eenie uk\u00e1\u017ee by\u0165 v\u00e4\u010d\u0161ie ako vypo\u010d\u00edtan\u00e9, zlyh\u00e1 z\u00e1vitovkov\u00fd reduktor okam\u017eite?<\/summary>\n
Nie okam\u017eite a nie je to predv\u00eddate\u013en\u00e9. Z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod pracuj\u00faci nad svojou hodnotou T\u2082n sa nezlom\u00ed pri prvom cykle pre\u0165a\u017eenia \u2013 katal\u00f3gov\u00e9 hodnotenie obsahuje bezpe\u010dnostn\u00fa rezervu a bronzov\u00e9 koleso sa pred zlomen\u00edm plasticky podd\u00e1. Postupom \u010dasu sa deje zr\u00fdchlen\u00e9 opotrebenie: povrch bronzov\u00e9ho kolesa prekro\u010d\u00ed n\u00e1vrhov\u00fd bod Hertzovho kontaktn\u00e9ho nap\u00e4tia, za\u010dne sa mikrokorozia, povrchov\u00fd materi\u00e1l sa odstra\u0148uje r\u00fdchlej\u0161ie, ako je projektovan\u00e9, a nakoniec sa hr\u00fabka zubov zmen\u0161\u00ed do bodu, kedy jednotka str\u00e1ca kr\u00fatiaci moment. Tento proces m\u00f4\u017ee trva\u0165 mesiace alebo roky v z\u00e1vislosti od toho, ako v\u00fdrazne za\u0165a\u017eenie prekro\u010d\u00ed T\u2082n. Porucha nie je dramatick\u00e1 \u2013 ide o postupn\u00e9 zvy\u0161ovanie v\u00f4le a hluku, po ktorom nakoniec nasleduje udalos\u0165 obmedzuj\u00faca kr\u00fatiaci moment. Ak m\u00e1te podozrenie, \u017ee v\u00e1\u0161 s\u00fa\u010dasn\u00fd z\u00e1vitovkov\u00fd reduk\u010dn\u00fd prevod je pre\u0165a\u017een\u00fd, zmerajte teplotu telesa a pri \u010fal\u0161ej v\u00fdmene oleja skontrolujte obsah medi v oleji \u2013 oboje s\u00fa v\u010dasn\u00e9 indik\u00e1tory predt\u00fdm, ako d\u00f4jde k mechanick\u00e9mu zlyhaniu.<\/div>\n<\/details>\n
\nKe\u010f vypo\u010d\u00edtan\u00e1 hodnota T_required spad\u00e1 medzi dve katal\u00f3gov\u00e9 ve\u013ekosti, mal by som si v\u017edy vybra\u0165 v\u00e4\u010d\u0161iu?<\/summary>\n
\u00c1no, v\u017edy si vyberte v\u00e4\u010d\u0161\u00ed model, ke\u010f po\u017eadovan\u00fd kr\u00fatiaci moment spad\u00e1 medzi dve \u0161tandardn\u00e9 ve\u013ekosti z\u00e1vitovkov\u00fdch reduktorov. Men\u0161ia jednotka by pracovala bl\u00edzko svojej kon\u0161truk\u010dnej hranice, tak\u017ee by nezost\u00e1vala \u017eiadna rezerva pre zmeny za\u0165a\u017eenia, zmeny teploty okolia, zmeny viskozity oleja alebo v\u00fdrobn\u00e9 tolerancie v poh\u00e1\u0148anom zariaden\u00ed. Rozdiel v n\u00e1kladoch medzi susedn\u00fdmi ve\u013ekos\u0165ami r\u00e1mov v z\u00e1vitovkovom reduktore je zvy\u010dajne mierny \u2013 ove\u013ea men\u0161\u00ed ako n\u00e1klady na skor\u00fa poruchu a nepl\u00e1novan\u00fa v\u00fdmenu. Jedin\u00e1 situ\u00e1cia, kedy je v\u00fdber men\u0161ej jednotky opodstatnen\u00fd, je vtedy, ke\u010f vypo\u010d\u00edtan\u00e1 hodnota T_required v\u00fdrazne podhodnocuje skuto\u010dn\u00e9 za\u0165a\u017eenie a m\u00e1te v \u00famysle v\u00fdpo\u010det prehodnoti\u0165 \u2013 v takom pr\u00edpade za\u010dnite najprv s presnej\u0161\u00edm meran\u00edm za\u0165a\u017eenia. Prezrite si na\u0161e rozsah \u0161nekov\u00fdch reduktorov<\/a> porovna\u0165 ve\u013ekosti susedn\u00fdch r\u00e1mov.<\/div>\n<\/details>\n<\/div>\n

<\/p>\n

\n

V\u00fdber a v\u00fdpo\u010dtov\u00e1 podpora \u0161nekov\u00e9ho prevodov\u00e9ho prevodu<\/h2>\n

In\u017einiersky t\u00edm spolo\u010dnosti Korea Ever-Power poskytuje overenie v\u00fdberu z\u00e1vitovkov\u00e9ho reduktora pre \u0161pecifick\u00e9 aplik\u00e1cie \u2013 vr\u00e1tane kontroly v\u00fdpo\u010dtu kr\u00fatiaceho momentu, potvrdenia prev\u00e1dzkov\u00e9ho faktora a pos\u00fadenia tepeln\u00e9ho v\u00fdkonu pre va\u0161e skuto\u010dn\u00e9 okolit\u00e9 a prev\u00e1dzkov\u00e9 podmienky. Pode\u013ete sa s nami o parametre va\u0161ej aplik\u00e1cie a my v\u00e1m vr\u00e1time kompletn\u00e9 odpor\u00fa\u010danie v\u00fdberu.<\/p>\n

Prehliada\u0165 \u0161nekov\u00e9 prevody<\/a>
\nPo\u0161lite n\u00e1m \u00fadaje z va\u0161ej \u017eiadosti<\/a><\/div>\n<\/div>\n<\/div>\n

Redaktor: Cxm<\/p>","protected":false},"excerpt":{"rendered":"

Worm Gear Reducer Torque and Ratio: The Calculation Guide Supplier recommendation tables are built around the average application. Your application has its specific load, duty cycle, ambient temperature, and shock character. This guide walks through the four core formulas and three worked examples so you can verify any worm gear reducer selection in under 20 […]<\/p>","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_et_pb_use_builder":"","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"categories":[1517],"tags":[218,363,365],"class_list":["post-1941","post","type-post","status-publish","format-standard","hentry","category-worm-gear-reducer","tag-worm-gear-reducer","tag-worm-gearbox","tag-worm-reducer-gearbox"],"_links":{"self":[{"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/posts\/1941","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/comments?post=1941"}],"version-history":[{"count":2,"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/posts\/1941\/revisions"}],"predecessor-version":[{"id":1943,"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/posts\/1941\/revisions\/1943"}],"wp:attachment":[{"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/media?parent=1941"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/categories?post=1941"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/worm-reducers.xyz\/sk\/wp-json\/wp\/v2\/tags?post=1941"}],"curies":[{"name":"pracovn\u00fd list","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}