{"id":1379,"date":"2021-01-15T08:04:00","date_gmt":"2021-01-15T08:04:00","guid":{"rendered":"http:\/\/worm-reducers.xyz\/?p=1379"},"modified":"2022-12-29T01:53:08","modified_gmt":"2022-12-29T01:53:08","slug":"conveyor-chain-selection","status":"publish","type":"post","link":"https:\/\/worm-reducers.xyz\/sk\/conveyor-chain-selection\/","title":{"rendered":"V\u00fdber dopravnej re\u0165aze"},"content":{"rendered":"

\u00davod
Pre presn\u00fd v\u00fdber dopravnej re\u0165aze je d\u00f4le\u017eit\u00e9 d\u00f4kladn\u00e9 pos\u00fadenie por\u00fach okolo dopravn\u00edka. T\u00e1to \u010das\u0165 rozober\u00e1 z\u00e1kladn\u00e9 aspekty potrebn\u00e9 pre \u00faspe\u0161n\u00fd v\u00fdber dopravnej re\u0165aze. Val\u010dekov\u00e9 re\u0165aze sa \u010dasto pou\u017e\u00edvaj\u00fa na manipul\u00e1ciu s \u013eahk\u00fdmi a\u017e stredne \u0165a\u017ek\u00fdmi materi\u00e1lmi. Environment\u00e1lne probl\u00e9my m\u00f4\u017eu vy\u017eadova\u0165 pou\u017eitie \u0161peci\u00e1lnych komponentov, povlakov, maz\u00edv alebo dokonca schopnos\u0165 pracova\u0165 bez dodato\u010dn\u00e9ho extern\u00e9ho mazania.
Z\u00e1kladn\u00e9 podrobnosti potrebn\u00e9 pre rozmanitos\u0165 re\u0165az\u00ed
Typ re\u0165azov\u00e9ho dopravn\u00edka (jednotkov\u00fd alebo sypk\u00fd) vr\u00e1tane dopravn\u00e9ho syst\u00e9mu (pr\u00edslu\u0161enstvo, vedr\u00e1, prechodov\u00e9 ty\u010de at\u010f.).
Usporiadanie dopravn\u00edka, ako napr\u00edklad umiestnenie ozuben\u00fdch kolies, sklony (ak existuj\u00fa) a po\u010det pou\u017eit\u00fdch prame\u0148ov re\u0165aze (N).
Mno\u017estvo materi\u00e1lu (M v lbs\/ft alebo kN\/m) a druh materi\u00e1lu, ktor\u00fd sa m\u00e1 dopravova\u0165.
Odhadovan\u00e1 hmotnos\u0165 \u010dast\u00ed dopravn\u00edka (W v lbs\/ft alebo kN\/m) spolu s re\u0165azou, lamelami alebo pr\u00eddavn\u00fdmi zariadeniami (ak existuj\u00fa).
Line\u00e1rne tempo re\u0165azca (S v ft\/min alebo m\/min).
Prostredie, v ktorom bude re\u0165az prev\u00e1dzkovan\u00e1, vr\u00e1tane teploty, podmienok kor\u00f3zie, stavu mazania at\u010f.
Krok 1: Odhad nap\u00e4tia v re\u0165azi
Na odhad \u0165ahu dopravn\u00edka (Pest) a n\u00e1sledne napnutia re\u0165aze (Test) pou\u017eite vzorec ni\u017e\u0161ie. Pest = (M + W) xfx SF a
Test = \u0160kodca \/ N
f = Koeficient trenia
SF = Faktor r\u00fdchlosti
Druh\u00e1 f\u00e1za: Predbe\u017en\u00fd v\u00fdber re\u0165azca
Pou\u017eit\u00edm kontrolnej hodnoty vytvorte predbe\u017en\u00fd sortiment v\u00fdberom re\u0165azca
ktor\u00e9ho menovit\u00e9 pracovn\u00e9 za\u0165a\u017eenie je v\u00e4\u010d\u0161ie v porovnan\u00ed s vypo\u010d\u00edtanou kontrolnou hodnotou. Tieto hodnoty s\u00fa vhodn\u00e9 pre prev\u00e1dzku dopravn\u00edka a l\u00ed\u0161ia sa od hodn\u00f4t uveden\u00fdch v tabu\u013ek\u00e1ch s prednou stranou z katal\u00f3gu, ktor\u00e9 s\u00favisia s vyu\u017eit\u00edm pomalobe\u017enej hnacej re\u0165aze.
Okrem dostato\u010dnej nosnosti musia ma\u0165 tieto re\u0165aze vo v\u0161eobecnosti ur\u010dit\u00fd rozstup, aby sa dosiahla po\u017eadovan\u00e1 vzdialenos\u0165 medzi upev\u0148ovac\u00edmi prvkami. Napr\u00edklad, ak sa maj\u00fa lamely priskrutkova\u0165 k upev\u0148ovaciemu prvku ka\u017ed\u00fdch 0,5 palca, rozstup zvolenej re\u0165aze by sa mal deli\u0165 na 1,5 palca. Preto by sa dala pou\u017ei\u0165 re\u0165az 40 (rozstup 1\/2 palca) s upev\u0148ovac\u00edmi prvkami ka\u017ed\u00fa tretinu, re\u0165az 60 (rozstup 3\/4 palca) s upev\u0148ovac\u00edmi prvkami ka\u017ed\u00fa sekundu, re\u0165az 120 (rozstup 1-1\/2 palca) s upev\u0148ovac\u00edmi prvkami v ka\u017edom rozstupe alebo dokonca re\u0165az C2060H (rozstup 1-1\/2 palca) s upev\u0148ovac\u00edmi prvkami v ka\u017edom rozstupe.
Tretia f\u00e1za: Finaliz\u00e1cia v\u00fdberu \u2013 Ur\u010denie skuto\u010dn\u00e9ho \u0165ahu dopravn\u00edka
Hne\u010f po vytvoren\u00ed predbe\u017en\u00e9ho sortimentu ho mus\u00edme overi\u0165 v\u00fdpo\u010dtom
skuto\u010dn\u00e9 nap\u00e4tie re\u0165aze (T). Aby sme to dokon\u010dili, mus\u00edme najprv vypo\u010d\u00edta\u0165 skuto\u010dn\u00fd \u0165ah dopravn\u00edka (P). Z va\u0161ich rozlo\u017een\u00ed uveden\u00fdch na pr\u00edslu\u0161nej strane tejto str\u00e1nky vyberte vhodn\u00fd vzorec a vypo\u010d\u00edtajte celkov\u00fd \u0165ah dopravn\u00edka. Upozor\u0148ujeme, \u017ee niektor\u00e9 dopravn\u00edky m\u00f4\u017eu by\u0165 kombin\u00e1ciou horizont\u00e1lnych, \u0161ikm\u00fdch a vertik\u00e1lnych... v takom pr\u00edpade ur\u010dte \u0165ah dopravn\u00edka v ka\u017edej jednotlivej sekcii a zahr\u0148te ich dokopy.
F\u00e1za \u0161tyri: V\u00fdpo\u010det optim\u00e1lneho nap\u00e4tia re\u0165aze
Maxim\u00e1lne nap\u00e4tie re\u0165aze (T) sa rovn\u00e1 \u0165ahovej sile dopravn\u00edka (P) vypo\u010d\u00edtanej vo f\u00e1ze 3, vydelenej po\u010dtom prame\u0148ov nes\u00facich za\u0165a\u017eenie (N), napr\u00edklad komponentu Pace (SF) uveden\u00fa v tabu\u013eke 2, viacprame\u0148ov\u00fd faktor (MSF) preuk\u00e1zan\u00e9 v tabu\u013eke tri plus probl\u00e9m s teplotou (TF) preuk\u00e1zan\u00e9 v tabu\u013eke 4.
T = (P \/ N) x MSF x SF x TF
Piata f\u00e1za: Skontrolujte menovit\u00e9 prev\u00e1dzkov\u00e9 za\u0165a\u017eenie v namontovanom re\u0165azci
Menovit\u00e9 pracovn\u00e9 za\u0165a\u017eenie vami vybranej re\u0165aze by malo by\u0165 vy\u0161\u0161ie ako maxim\u00e1lne nap\u00e4tie re\u0165aze (T) vypo\u010d\u00edtan\u00e9 vo f\u00e1ze 4 vy\u0161\u0161ie. Tieto hodnoty s\u00fa prijate\u013en\u00e9 pre prev\u00e1dzku dopravn\u00edka, a preto sa l\u00ed\u0161ia od hodn\u00f4t uveden\u00fdch v tabu\u013ek\u00e1ch na za\u010diatku katal\u00f3gu, ktor\u00e9 sa t\u00fdkaj\u00fa pou\u017eitia n\u00edzkor\u00fdchlostn\u00fdch hnac\u00edch re\u0165az\u00ed.
Krok \u0161es\u0165: Overte \u201epr\u00edpustn\u00e9 za\u0165a\u017eenie val\u010deka\u201c na vybranej re\u0165azi
Pri re\u0165aziach, ktor\u00e9 sa ot\u00e1\u010daj\u00fa okolo val\u010dekov re\u0165aze alebo na vysoko hodnoten\u00fdch val\u010dekov\u00fdch upevneniach, m\u00f4\u017ee by\u0165 potrebn\u00e9 skontrolova\u0165 povolen\u00e9 za\u0165a\u017eenie val\u010dekov.
Pozn\u00e1mka: Za\u0165a\u017eenie val\u010deka je ur\u010den\u00e9:
Za\u0165a\u017eenie val\u010deka = Wr \/ Nr
Wr = Celkov\u00e1 hmotnos\u0165 nesen\u00e1 val\u010dekmi
Nr = Po\u010det val\u010dekov podopieraj\u00facich nadmern\u00fa hmotnos\u0165.<\/p>","protected":false},"excerpt":{"rendered":"

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