{"id":1941,"date":"2026-04-17T05:04:15","date_gmt":"2026-04-17T05:04:15","guid":{"rendered":"https:\/\/worm-reducers.xyz\/?p=1941"},"modified":"2026-04-17T05:04:15","modified_gmt":"2026-04-17T05:04:15","slug":"worm-gear-reducer-torque-and-ratio-the-calculation-guide","status":"publish","type":"post","link":"https:\/\/worm-reducers.xyz\/cs\/worm-gear-reducer-torque-and-ratio-the-calculation-guide\/","title":{"rendered":"To\u010div\u00fd moment a p\u0159evodov\u00fd pom\u011br \u0161nekov\u00e9ho p\u0159evodu: Pr\u016fvodce v\u00fdpo\u010dtem"},"content":{"rendered":"
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To\u010div\u00fd moment a p\u0159evodov\u00fd pom\u011br \u0161nekov\u00e9ho p\u0159evodu: Pr\u016fvodce v\u00fdpo\u010dtem<\/h1>\n

Tabulky doporu\u010den\u00ed dodavatel\u016f jsou sestaveny na z\u00e1klad\u011b pr\u016fm\u011brn\u00e9 aplikace. Va\u0161e aplikace m\u00e1 specifick\u00e9 zat\u00ed\u017een\u00ed, pracovn\u00ed cyklus, okoln\u00ed teplotu a charakter r\u00e1z\u016f. Tato p\u0159\u00edru\u010dka v\u00e1s provede \u010dty\u0159mi z\u00e1kladn\u00edmi vzorci a t\u0159emi praktick\u00fdmi p\u0159\u00edklady, abyste si mohli ov\u011b\u0159it jak\u00e9koli \u0161nekov\u00fd reduktor<\/strong> v\u00fdb\u011br za m\u00e9n\u011b ne\u017e 20 minut.<\/p>\n

Z\u00edskejte podporu pro v\u00fdpo\u010dty<\/a><\/p>\n<\/div>\n<\/div>\n

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Pro\u010d byste si m\u011bli v\u017edycky po\u010d\u00edtat sami<\/h2>\n
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Tabulky doporu\u010den\u00ed dodavatel\u016f jsou sestaveny pro st\u0159edn\u00ed aplikaci \u2013 rovnom\u011brn\u00e9 zat\u00ed\u017een\u00ed, 8 hodin denn\u011b, okoln\u00ed teplota 20 \u00b0C, minim\u00e1ln\u00ed ot\u0159esy. Poka\u017ed\u00e9, kdy\u017e se n\u011bkter\u00e1 z t\u011bchto podm\u00ednek li\u0161\u00ed od va\u0161\u00ed skute\u010dn\u00e9 aplikace, m\u016f\u017ee b\u00fdt doporu\u010den\u00ed chybn\u00e9. Ne nebezpe\u010dn\u011b chybn\u00e9, ale ti\u0161e chybn\u00e9 zp\u016fsobem, kter\u00fd vede k poru\u0161e po 6 000 hodin\u00e1ch m\u00edsto 20 000 hodin\u00e1ch a nikdo ji nikdy nevysleduje zp\u011bt k p\u016fvodn\u00edmu stavu. \u0161nekov\u00fd reduktor<\/strong> v\u00fdb\u011br.<\/p>\n

V\u00fdpo\u010det nen\u00ed slo\u017eit\u00fd \u2013 jedn\u00e1 se o \u010dty\u0159i vzorce, jejich\u017e v\u00fdpo\u010dty zaberou 15 minut p\u0159i prvn\u00ed aplikaci a 5 minut p\u0159i ka\u017ed\u00e9 dal\u0161\u00ed aplikaci. Samostatn\u00e9 v\u00fdpo\u010dty v\u00e1s tak\u00e9 nut\u00ed p\u0159esn\u011b definovat va\u0161i aplikaci: skute\u010dn\u00fd v\u00fdstupn\u00ed to\u010div\u00fd moment, nikoli p\u0159ibli\u017en\u00fd; skute\u010dn\u00fd pracovn\u00ed cyklus, nikoli \u201ep\u0159eru\u0161ovan\u00fd\u201c; skute\u010dn\u00e1 okoln\u00ed teplota, nikoli \u201epokojov\u00e1 teplota\u201c.<\/p>\n

Nej\u010dast\u011bj\u0161\u00ed chyby p\u0159i dimenzov\u00e1n\u00ed \u0161nekov\u00e9ho reduktoru \u2013 poddimenzovan\u00fd provozn\u00ed sou\u010dinitel, ignorovan\u00fd limit tepeln\u00e9ho v\u00fdkonu, podhodnocen\u00e1 okoln\u00ed teplota \u2013 jsou v tabulce doporu\u010den\u00ed neviditeln\u00e9 a viditeln\u00e9 v 15minutov\u00e9m v\u00fdpo\u010dtu.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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\u010cty\u0159i z\u00e1kladn\u00ed vzorce<\/h2>\n

Ka\u017ed\u00fd v\u00fdpo\u010det v\u00fdb\u011bru \u0161nekov\u00e9ho reduktoru pou\u017e\u00edv\u00e1 tyto \u010dty\u0159i vzorce. Ty na sebe navazuj\u00ed postupn\u011b \u2013 vypo\u010d\u00edtejte je v po\u0159ad\u00ed a m\u00e1te kompletn\u00ed z\u00e1klad pro v\u00fdb\u011br.<\/p>\n

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FORMULE 1<\/div>\n

Reduk\u010dn\u00ed pom\u011br<\/h3>\n
i = n_vstup\u016f \u00f7 n_v\u00fdstup\u016f<\/div>\n

Kde:<\/strong> n_vstup = ot\u00e1\u010dky h\u0159\u00eddele motoru (ot\/min); n_v\u00fdstup = po\u017eadovan\u00e9 ot\u00e1\u010dky v\u00fdstupn\u00ed h\u0159\u00eddele (ot\/min)<\/p>\n

P\u0159\u00edklad:<\/strong> Motor 1 450 ot\/min, po\u017eadovan\u00fd v\u00fdkon 29 ot\/min: i = 1 450 \u00f7 29 = 50:1<\/strong><\/p>\n

Praktick\u00e1 pozn\u00e1mka:<\/strong> Standardn\u00ed p\u0159evodov\u00e9 pom\u011bry jsou 5, 7,5, 10, 15, 20, 25, 30, 40, 50, 60, 80, 100. Pokud se v\u00e1\u0161 vypo\u010d\u00edtan\u00fd p\u0159evodov\u00fd pom\u011br nach\u00e1z\u00ed mezi dv\u011bma standardn\u00edmi hodnotami, v\u017edy zaokrouhlete nahoru na vy\u0161\u0161\u00ed p\u0159evodov\u00fd pom\u011br (ni\u017e\u0161\u00ed v\u00fdstupn\u00ed ot\u00e1\u010dky) \u2013 nikdy nezaokrouhlete dol\u016f.<\/p>\n<\/div>\n

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FORMULE 2<\/div>\n

V\u00fdstupn\u00ed to\u010div\u00fd moment (teoretick\u00fd)<\/h3>\n
T\u2082 = T\u2081 \u00d7 i \u00d7 \u03b7<\/div>\n

Kde:<\/strong> T\u2081 = to\u010div\u00fd moment na h\u0159\u00eddeli motoru (N\u00b7m); i = p\u0159evodov\u00fd pom\u011br; \u03b7 = \u00fa\u010dinnost p\u0159i tomto p\u0159evodov\u00e9m pom\u011bru (desetinn\u011b)<\/p>\n

D\u016fle\u017eit\u00e9:<\/strong> \u00da\u010dinnost \u03b7 nen\u00ed konstantn\u00ed \u2013 z\u00e1vis\u00ed na zvolen\u00e9m pom\u011bru. Viz referen\u010dn\u00ed tabulka \u00fa\u010dinnosti v kapitole 4.<\/p>\n

P\u0159\u00edklad:<\/strong> T\u2081 = 4,0 N\u00b7m (motor), i = 50, \u03b7 = 0,60: T\u2082 = 4,0 \u00d7 50 \u00d7 0,60 = 120 N\u00b7m<\/strong><\/p>\n<\/div>\n

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FORMULE 3<\/div>\n

Po\u017eadovan\u00fd vstupn\u00ed v\u00fdkon<\/h3>\n
P_vstup = (T\u2082 \u00d7 n\u2082) \u00f7 (9 550 \u00d7 \u03b7)<\/div>\n

Jednotky:<\/strong> P_p\u0159\u00edkon v kW; T\u2082 v N\u00b7m; n\u2082 v ot\/min<\/p>\n

Konstanta 9 550 p\u0159ev\u00e1d\u00ed mezi rota\u010dn\u00ed a v\u00fdkonovou jednotkou. Jedn\u00e1 se o v\u00fdkon, kter\u00fd mus\u00ed motor dod\u00e1vat \u2013 nikoli o katalogov\u00fd v\u00fdkon motoru.<\/p>\n

P\u0159\u00edklad:<\/strong> T\u2082 = 120 N\u00b7m, n\u2082 = 29 ot\/min, \u03b7 = 0,60: P_vstup = (120 \u00d7 29) \u00f7 (9 550 \u00d7 0,60) = 0,607 kW<\/strong><\/p>\n<\/div>\n

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FORMULE 4<\/div>\n

Korekce servisn\u00edho faktoru<\/h3>\n
Po\u017eadovan\u00e1_T = Skute\u010dn\u00e1_T \u00d7 SF<\/div>\n

P\u0159ed porovn\u00e1n\u00edm s katalogov\u00fdm jmenovit\u00fdm momentem aplikujte SF na skute\u010dn\u00fd po\u017eadovan\u00fd v\u00fdstupn\u00ed moment. Katalogov\u00fd T\u2082n mus\u00ed b\u00fdt \u2265 T_required.<\/p>\n

P\u0159\u00edklad:<\/strong> T_skute\u010dn\u00e1 = 120 N\u00b7m, SF = 1,5 (lehk\u00fd r\u00e1z, 8 h\/den): T_po\u017eadovan\u00e1 = 120 \u00d7 1,5 = 180 N\u00b7m<\/strong><\/p>\n

Vyberte \u0161nekov\u00fd reduktor s katalogov\u00fdm T\u2082n \u2265 180 N\u00b7m p\u0159i p\u0159evodov\u00e9m pom\u011bru 50:1.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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Pr\u016fvodce servisn\u00edm faktorem (SF): Parametr, kter\u00fd je nej\u010dast\u011bji podce\u0148ov\u00e1n<\/h2>\n
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Provozn\u00ed faktor zohled\u0148uje skute\u010dn\u00e9 podm\u00ednky zat\u00ed\u017een\u00ed vzhledem k katalogov\u00fdm zku\u0161ebn\u00edm podm\u00ednk\u00e1m. Katalogov\u00e9 jmenovit\u00e9 hodnoty \u0161nekov\u00e9ho p\u0159evodu p\u0159edpokl\u00e1daj\u00ed rovnom\u011brn\u00e9 zat\u00ed\u017een\u00ed p\u0159i jmenovit\u00fdch ot\u00e1\u010dk\u00e1ch po celou dobu trv\u00e1n\u00ed zkou\u0161ky. Ka\u017ed\u00e1 odchylka od t\u00e9to z\u00e1kladn\u00ed hodnoty zvy\u0161uje efektivn\u00ed zat\u00ed\u017een\u00ed ozuben\u00fdch kol a lo\u017eisek. SF p\u0159ev\u00e1d\u00ed va\u0161e skute\u010dn\u00e9 provozn\u00ed podm\u00ednky do ekvivalentn\u00edho po\u017eadavku na v\u00fdb\u011br z katalogu.<\/p>\n

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\n\n\n\n\n\n\n\n\n
Na\u010d\u00edst znak<\/th>\n\u22642 h\/den<\/th>\n2\u201310 h\/den<\/th>\n>10 h\/den<\/th>\n<\/tr>\n<\/thead>\n
Rovnom\u011brn\u00e9 zat\u00ed\u017een\u00ed<\/td>\n1.00<\/td>\n1.25<\/td>\n1.50<\/td>\n<\/tr>\n
Lehk\u00fd \u0161ok<\/td>\n1.25<\/td>\n1.50<\/td>\n1.75<\/td>\n<\/tr>\n
M\u00edrn\u00fd \u0161ok<\/td>\n1.50<\/td>\n1.75<\/td>\n2.00<\/td>\n<\/tr>\n
Siln\u00fd \u0161ok<\/td>\n1.75<\/td>\n2.00<\/td>\n2.25<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

Typick\u00e9 p\u0159\u00edklady vybaven\u00ed podle kategorie tlumi\u010d\u016f<\/h3>\n
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Jednotn\u00fd:<\/strong> Odst\u0159ediv\u00e9 ventil\u00e1tory, odst\u0159ediv\u00e1 \u010derpadla, lehk\u00e9 dopravn\u00edkov\u00e9 p\u00e1sy (bez rozb\u011bhu pod zat\u00ed\u017een\u00edm), balic\u00ed stroje s konstantn\u00ed rychlost\u00ed.<\/div>\n
Lehk\u00fd \u0161ok:<\/strong> Dopravn\u00edky, kter\u00e9 se spou\u0161t\u011bj\u00ed pod zat\u00ed\u017een\u00edm, m\u00edchadla s kapalinami s rovnom\u011brnou viskozitou, b\u011b\u017en\u00e9 tov\u00e1rn\u00ed stroje s ob\u010dasn\u00fdmi zm\u011bnami zat\u00ed\u017een\u00ed.<\/div>\n
M\u00edrn\u00fd \u0161ok:<\/strong> Kompresory, m\u00edcha\u010dky s prom\u011bnn\u00fdm d\u00e1vkov\u00e1n\u00edm suspenze, \u0161nekov\u00e9 dopravn\u00edky, navij\u00e1ky, kore\u010dkov\u00e9 elev\u00e1tory, s\u00edtov\u00e9 podava\u010de.<\/div>\n
Siln\u00fd \u0161ok:<\/strong> Vibra\u010dn\u00ed podava\u010de, \u010delistn\u00ed drti\u010de, t\u0159\u00eddic\u00ed za\u0159\u00edzen\u00ed na rudu, kladivov\u00e9 ml\u00fdny, pomocn\u00e1 za\u0159\u00edzen\u00ed pro vrt\u00e1n\u00ed hornin.<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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\u00da\u010dinnost vs. pom\u011br: Referen\u010dn\u00ed data, kter\u00e1 pot\u0159ebujete pro ka\u017ed\u00fd v\u00fdpo\u010det<\/h2>\n
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\u00da\u010dinnost \u0161nekov\u00e9ho reduktoru nen\u00ed jednotn\u00e1 pevn\u00e1 hodnota \u2013 v\u00fdrazn\u011b se m\u011bn\u00ed s p\u0159evodov\u00fdm pom\u011brem. Pou\u017eit\u00ed nespr\u00e1vn\u00e9 hodnoty \u00fa\u010dinnosti ve v\u00fdpo\u010dtu vede k nespr\u00e1vn\u00e9mu vstupn\u00edmu v\u00fdkonu a nespr\u00e1vn\u00e9mu odhadu to\u010div\u00e9ho momentu. N\u00e1sleduj\u00edc\u00ed tabulka uv\u00e1d\u00ed realistick\u00e9 rozsahy pro \u0161nekov\u00e9 reduktory \u0159ady WP a NMRV s pou\u017eit\u00edm standardn\u00edho miner\u00e1ln\u00edho oleje ISO VG 220 p\u0159i provozn\u00ed teplot\u011b.<\/p>\n

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Pom\u011br (i)<\/th>\n\u00da\u010dinnost \u03b7 Rozsah<\/th>\nPou\u017eit\u00ed ve v\u00fdpo\u010dtu<\/th>\n<\/tr>\n<\/thead>\n
7.5:1<\/td>\n85\u201390%<\/td>\n\u03b7 = 0,87<\/td>\n<\/tr>\n
10:1<\/td>\n80\u201385%<\/td>\n\u03b7 = 0,82<\/td>\n<\/tr>\n
20:1<\/td>\n70\u201378%<\/td>\n\u03b7 = 0,74<\/td>\n<\/tr>\n
30:1<\/td>\n65\u201373%<\/td>\n\u03b7 = 0,69<\/td>\n<\/tr>\n
40:1<\/td>\n60\u201368%<\/td>\n\u03b7 = 0,64<\/td>\n<\/tr>\n
50:1<\/td>\n55\u201364%<\/td>\n\u03b7 = 0,60<\/td>\n<\/tr>\n
60:1<\/td>\n50\u201358%<\/td>\n\u03b7 = 0,54<\/td>\n<\/tr>\n
80\u2013100:1<\/td>\n44\u201355%<\/td>\n\u03b7 = 0,49<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

Horn\u00ed hranice rozsahu: kolo z bronzu s vysok\u00fdm obsahem c\u00ednu (10%+ Sn), p\u0159esn\u011b brou\u0161en\u00e1 \u0161nekov\u00e1 h\u0159\u00eddel, syntetick\u00fd olej PAO. Doln\u00ed hranice: standardn\u00ed bronz, \u0159ezan\u00fd \u0161nekov\u00fd h\u0159\u00eddel, miner\u00e1ln\u00ed olej. Pro konzervativn\u00ed dimenzov\u00e1n\u00ed pou\u017eijte spodn\u00ed hodnotu rozsahu.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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T\u0159i kompletn\u00ed vy\u0159e\u0161en\u00e9 p\u0159\u00edklady<\/h2>\n

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P\u0159\u00edklad 1: Pohon dopravn\u00edku (rovnom\u011brn\u00e9 zat\u00ed\u017een\u00ed, 8 h\/den)<\/h3>\n
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Vzhledem k:<\/strong> P\u00e1sov\u00fd dopravn\u00edk. Rychlost p\u00e1su 1,2 m\/s. Pr\u016fm\u011br hnac\u00edho bubnu 300 mm. Hmotnost p\u00e1su s n\u00e1kladem 800 kg. Sou\u010dinitel t\u0159en\u00ed \u03bc = 0,05. Provoz 8 hodin denn\u011b, rovnom\u011brn\u00e9 zat\u00ed\u017een\u00ed.<\/p>\n

Krok 1 \u2013 Po\u017eadovan\u00e9 ot\u00e1\u010dky bubnu:<\/strong>
\nn_buben = (v \u00d7 60) \/ (\u03c0 \u00d7 D) = (1,2 \u00d7 60) \/ (\u03c0 \u00d7 0,30) = 76 ot.\/min.<\/p>\n

Krok 2 \u2013 S\u00edla a to\u010div\u00fd moment \u0159emenov\u00e9ho pohonu:<\/strong>
\nF = m \u00d7 g \u00d7 \u03bc = 800 \u00d7 9,81 \u00d7 0,05 = 392 N
\nT_buben = F \u00d7 r = 392 \u00d7 0,15 = 58,8 N\u00b7m<\/strong><\/p>\n

Krok 3 \u2013 Pom\u011br:<\/strong>
\ni = 1 450 \/ 76 = 19,1 \u2192 vyberte 20:1<\/strong><\/p>\n<\/div>\n

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Krok 4 \u2013 Aplikace SF:<\/strong>
\nSF = 1,25 (rovnom\u011brn\u00e9 zat\u00ed\u017een\u00ed, 8 h\/den)
\nPo\u017eadovan\u00e1_t = 58,8 \u00d7 1,25 = 73,5 N\u00b7m<\/strong><\/p>\n

Krok 5 \u2013 Ov\u011b\u0159en\u00ed vstupn\u00edho nap\u00e1jen\u00ed:<\/strong>
\n\u03b7 p\u0159i 20:1 = 0,74
\nP_vstup = (58,8 \u00d7 76) \/ (9 550 \u00d7 0,74) = 0,63 kW<\/strong><\/p>\n

Krok 6 \u2013 Tepeln\u00e1 kontrola:<\/strong>
\nTrval\u00fd provoz p\u0159i 20 \u00b0C: P_th pro NMRV-050 p\u0159i 20:1 = cca 3,2 kW \u226b 0,63 kW. Tepeln\u00e1 rezerva je dostate\u010dn\u00e1.<\/p>\n

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\u2713 Vybr\u00e1no: NMRV-050 v pom\u011bru 20:1<\/strong>
\nKatalogov\u00fd T\u2082n \u2265 73,5 N\u00b7m p\u0159i 20:1. Motor: 0,75 kW (dal\u0161\u00ed standardn\u00ed velikost nad 0,63 kW).<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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P\u0159\u00edklad 2: Pohon m\u00edchadla (st\u0159edn\u00ed r\u00e1zy, 16 h\/den)<\/h3>\n
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Vzhledem k:<\/strong> Pr\u016fmyslov\u00e9 m\u00edchadlo kalu. Po\u017eadovan\u00fd v\u00fdstupn\u00ed to\u010div\u00fd moment 320 N\u00b7m p\u0159i 28 ot\/min. Provoz 16 hodin denn\u011b, m\u00edrn\u00e9 r\u00e1zy (prom\u011bnn\u00e1 hustota kalu). Okoln\u00ed teplota 30 \u00b0C. Otev\u0159en\u00e1 instalace.<\/p>\n

Krok 1 \u2013 Pom\u011br:<\/strong>
\ni = 1 450 \/ 28 = 51,8 \u2192 vyberte 50:1<\/strong>
\n(Skute\u010dn\u00e9 v\u00fdstupn\u00ed ot\u00e1\u010dky = 1 450 \/ 50 = 29 ot\/min \u2013 p\u0159ijateln\u00e9)<\/p>\n

Krok 2 \u2013 Aplikace SF:<\/strong>
\nSF = 2,00 (st\u0159edn\u011b siln\u00fd \u0161ok, >10 h\/den)
\nPo\u017eadovan\u00e1_t = 320 \u00d7 2,00 = 640 N\u00b7m<\/strong><\/p>\n<\/div>\n

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Krok 3 \u2013 Vstupn\u00ed v\u00fdkon:<\/strong>
\n\u03b7 p\u0159i 50:1 = 0,60
\nP_vstup = (320 \u00d7 28) \/ (9 550 \u00d7 0,60) = 1,56 kW<\/strong><\/p>\n

Krok 4 \u2013 Tepeln\u00e1 kontrola p\u0159i 30 \u00b0C:<\/strong>
\nFaktor okoln\u00ed teploty p\u0159i 30 \u00b0C = 0,87
\nNMRV-090 p\u0159i 50:1 P_th katalog = 4,8 kW
\nKorigovan\u00fd P_th = 4,8 \u00d7 0,87 = 4,18 kW \u226b 1,56 kW. \u2713<\/p>\n

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\u2713 Vybr\u00e1no: NMRV-090 p\u0159i 50:1<\/strong>
\nT\u2082n p\u0159i 50:1 mus\u00ed b\u00fdt \u2265 640 N\u00b7m. Ov\u011b\u0159te v katalogu. Motor: 2,2 kW.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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P\u0159\u00edklad 3: Pomocn\u00fd pohon zved\u00e1ku (siln\u00e9 r\u00e1zy, p\u0159eru\u0161ovan\u00e9)<\/h3>\n
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Vzhledem k:<\/strong> Pohon bubnu pomocn\u00e9ho kladkostroje. Zvedac\u00ed hmotnost 1 200 kg. Rychlost zdvihu 0,4 m\/s. Pr\u016fm\u011br bubnu 400 mm. Pracovn\u00ed cyklus: 15 sekund zapnuto, 45 sekund vypnuto. Vy\u017eaduje se samosvorn\u00e9 uzam\u010den\u00ed.<\/p>\n

Krok 1 \u2013 Utahovac\u00ed moment bubnu:<\/strong>
\nF = 1 200 \u00d7 9,81 = 11 772 N
\nT_buben = F \u00d7 r = 11 772 \u00d7 0,20 = 2 354 N\u00b7m<\/strong><\/p>\n

Krok 2 \u2013 Ot\u00e1\u010dky bubnu:<\/strong>
\nn_buben = (0,4 \u00d7 60) \/ (\u03c0 \u00d7 0,40) = 19,1 ot.\/min.
\nPom\u011br: i = 1,450 \/ 19,1 = 75,9 \u2192 80:1<\/strong> (samostatn\u00e9 uzam\u010den\u00ed potvrzeno)<\/p>\n<\/div>\n

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Krok 3 \u2013 Efektivn\u00ed v\u00fdkon v pracovn\u00edm cyklu:<\/strong>
\nDC = 15\/(15+45) = 25%
\nP_eff = P_peak \u00d7 \u221a(DC) = P_peak \u00d7 0,50<\/p>\n

Krok 4 \u2013 Aplikace SF:<\/strong>
\nSF = 1,75 (siln\u00fd \u0161ok, ekvivalent \u22642 h\/den)
\nPo\u017eadovan\u00e1_t = 2,354 \u00d7 1,75 = 4 120 N\u00b7m<\/strong><\/p>\n

P_vstupn\u00ed vrchol:<\/strong> \u03b7 p\u0159i 80:1 = 0,50
\nP_peak = (2 354 \u00d7 19,1) \/ (9 550 \u00d7 0,50) = 9,43 kW<\/strong><\/p>\n

\n

\u2713 Vybr\u00e1no: WP135 p\u0159i 80:1<\/strong>
\nT\u2082n \u2265 4 120 N\u00b7m. Motor: 11 kW. Tepeln\u00e1 kontrola: P_eff = 9,43 \u00d7 0,50 = 4,7 kW \u2013 ov\u011b\u0159te P_th pro WP135 p\u0159i 80:1 p\u0159i skute\u010dn\u00e9 okoln\u00ed teplot\u011b.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

<\/p>\n

\n

Ov\u011b\u0159en\u00ed tepeln\u00e9ho v\u00fdkonu: Kontrola, kter\u00e1 zabra\u0148uje poruch\u00e1m zp\u016fsoben\u00fdm p\u0159eh\u0159\u00e1t\u00edm<\/h2>\n
\n
\n

Pro jakoukoli aplikaci s nep\u0159etr\u017eit\u00fdm provozem (S1 nebo pracovn\u00ed cyklus >50%) je ov\u011b\u0159en\u00ed tepeln\u00e9ho v\u00fdkonu povinn\u00fdm dal\u0161\u00edm krokem po v\u00fdpo\u010dtu to\u010div\u00e9ho momentu\/p\u0159evodov\u00e9ho pom\u011bru. Mnoho spr\u00e1vn\u011b dimenzovan\u00fdch \u0161nekov\u00fdch reduktor\u016f \u2013 s ov\u011b\u0159en\u00fdm to\u010div\u00fdm momentem a p\u0159evodov\u00fdm pom\u011brem \u2013 selhalo, proto\u017ee nebyl nikdy zkontrolov\u00e1n limit tepeln\u00e9ho v\u00fdkonu.<\/p>\n

<\/p>\n

Postup tepeln\u00e9ho ov\u011b\u0159en\u00ed:<\/strong><\/p>\n

1.<\/strong> Z v\u00fdpo\u010dtu zaznamenejte skute\u010dn\u00fd trval\u00fd vstupn\u00ed v\u00fdkon P_input (kW).<\/p>\n

2.<\/strong> Z vybran\u00e9ho katalogu \u0161nekov\u00fdch reduktor\u016f vyhledejte P_th p\u0159i zvolen\u00e9m p\u0159evodov\u00e9m pom\u011bru.<\/p>\n

3.<\/strong> Pou\u017eijte korek\u010dn\u00ed faktor okoln\u00ed teploty (\u00faplnou tabulku naleznete v \u010dl\u00e1nku K-05).<\/p>\n

4.<\/strong> Pokud je p\u0159ilo\u017eena, prove\u010fte korekci instalace (ode\u010dt\u011bte 15\u201325%).<\/p>\n

5.<\/strong> Potvr\u010fte, \u017ee P_input < P_th (opraveno). Pokud ne, upgradujte na dal\u0161\u00ed velikost r\u00e1mu nebo p\u0159idejte chlazen\u00ed.<\/p>\n

\n

Korejsk\u00e1 letn\u00ed pozn\u00e1mka:<\/strong> P\u0159i okoln\u00ed teplot\u011b 35 \u00b0C je korigovan\u00e1 hodnota P_th p\u0159ibli\u017en\u011b 80% katalogov\u00e9 hodnoty. \u0160nekov\u00fd p\u0159evodov\u00fd stupe\u0148 vybran\u00fd v katalogov\u00e9 hodnot\u011b P_th bez korekce na okoln\u00ed teplotu bude v tepl\u00fdch letn\u00edch dnech p\u0159ekra\u010dovat sv\u016fj tepeln\u00fd limit \u2013 i kdy\u017e v zim\u011b b\u011b\u017e\u00ed bez probl\u00e9m\u016f. V\u017edy pou\u017e\u00edvejte korekci na okoln\u00ed teplotu.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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\u010cty\u0159i chyby ve v\u00fdpo\u010dtech, kter\u00e9 se objevuj\u00ed nej\u010dast\u011bji<\/h2>\n
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Chyba 1: Pou\u017eit\u00ed v\u00fdkonu motoru z typov\u00e9ho \u0161t\u00edtku jako v\u00fdkonu aplikace<\/h3>\n

Motor o v\u00fdkonu 2,2 kW poh\u00e1n\u011bj\u00edc\u00ed lehce zat\u00ed\u017een\u00fd dopravn\u00edk m\u016f\u017ee za skute\u010dn\u00fdch provozn\u00edch podm\u00ednek dodat na h\u0159\u00eddeli pouze 0,8 kW. Pou\u017eit\u00ed 2,2 kW ve v\u00fdpo\u010dtu nadhodnocuje vstupn\u00ed v\u00fdkon o 175%, co\u017e vede k \u00fadaji o vstupn\u00edm v\u00fdkonu, kter\u00fd zp\u016fsobuje, \u017ee tepeln\u00e1 kontrola vypad\u00e1 hor\u0161\u00ed ne\u017e skute\u010dnost.<\/p>\n

Spr\u00e1vn\u00fd p\u0159\u00edstup:<\/strong> Vypo\u010d\u00edtejte skute\u010dn\u00fd po\u017eadovan\u00fd vstupn\u00ed v\u00fdkon z parametr\u016f z\u00e1t\u011b\u017ee (vzorce 2 a 3). Typov\u00fd \u0161t\u00edtek motoru pou\u017eijte pouze k ov\u011b\u0159en\u00ed, \u017ee je motor dostate\u010dn\u011b velk\u00fd \u2013 ne jako vstupn\u00ed v\u00fdkon pro tepeln\u00e9 posouzen\u00ed.<\/p>\n<\/div>\n

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Chyba 2: Porovn\u00e1n\u00ed skute\u010dn\u00e9ho to\u010div\u00e9ho momentu p\u0159\u00edmo s katalogov\u00fdm T\u2082n bez SF<\/h3>\n

Katalogov\u00e1 hodnota T\u2082n je jmenovit\u00e1 hodnota zku\u0161ebn\u00edch podm\u00ednek. To\u010div\u00fd moment va\u0161\u00ed aplikace vyn\u00e1soben\u00fd hodnotou SF mus\u00ed b\u00fdt ni\u017e\u0161\u00ed ne\u017e T\u2082n. Vynech\u00e1n\u00ed hodnoty SF znamen\u00e1 v\u00fdb\u011br \u0161nekov\u00e9ho p\u0159evodu, kter\u00fd spl\u0148uje pr\u016fm\u011brn\u00fd po\u017eadavek na to\u010div\u00fd moment, ale selh\u00e1v\u00e1 p\u0159i \u0161pi\u010dkov\u00e9m po\u017eadavku, kter\u00fd se vyskytuje des\u00edtkykr\u00e1t za provozn\u00ed cyklus.<\/p>\n

Spr\u00e1vn\u00fd p\u0159\u00edstup:<\/strong> P\u0159ed prohl\u00e9dnut\u00edm katalogu v\u017edy vypo\u010d\u00edtejte T_required = T_actual \u00d7 SF. Nikdy neporovn\u00e1vejte hrub\u00fd aplika\u010dn\u00ed moment s T\u2082n.<\/p>\n<\/div>\n

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Chyba 3: Pou\u017eit\u00ed katalogov\u00e9 \u00fa\u010dinnosti pro tepeln\u00e9 v\u00fdpo\u010dty<\/h3>\n

Hodnoty \u00fa\u010dinnosti uveden\u00e9 v katalogu p\u0159edstavuj\u00ed nejlep\u0161\u00ed p\u0159\u00edpad \u2013 pln\u00e9 zat\u00ed\u017een\u00ed, provozn\u00ed teplota, p\u0159esn\u011b brou\u0161en\u00fd \u0161nek, vysoce kvalitn\u00ed olej. P\u0159i \u010d\u00e1ste\u010dn\u00e9m zat\u00ed\u017een\u00ed, studen\u00e9m startu nebo se standardn\u00edmi komponenty je \u00fa\u010dinnost ni\u017e\u0161\u00ed \u2013 co\u017e znamen\u00e1, \u017ee se generuje v\u00edce tepla v pom\u011bru k v\u00fdstupn\u00edmu v\u00fdkonu.<\/p>\n

Spr\u00e1vn\u00fd p\u0159\u00edstup:<\/strong> Pro v\u00fdpo\u010dty tepeln\u00e9ho v\u00fdkonu pou\u017eijte spodn\u00ed hranici rozsahu \u00fa\u010dinnosti (konzervativn\u00ed hodnotu), nikoli katalogovou \u0161pi\u010dkovou hodnotu. Ve v\u00fdpo\u010dtu se m\u00fdl\u00edte na stranu generov\u00e1n\u00ed v\u011bt\u0161\u00edho mno\u017estv\u00ed tepla.<\/p>\n<\/div>\n

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Chyba 4: Ignorov\u00e1n\u00ed okoln\u00ed teploty p\u0159i tepeln\u00e9 kontrole<\/h3>\n

Tepeln\u00fd v\u00fdkon P_th ka\u017ed\u00e9ho \u0161nekov\u00e9ho reduktoru je specifikov\u00e1n p\u0159i okoln\u00ed teplot\u011b 20 \u00b0C. V korejsk\u00e9m pr\u016fmyslov\u00e9m prost\u0159ed\u00ed je norm\u00e1ln\u00ed letn\u00ed okoln\u00ed teplota 30\u201335 \u00b0C. P\u0159i 35 \u00b0C klesne P_th na 80% katalogov\u00e9 hodnoty \u2013 co\u017e je hodnota, kter\u00e1 prom\u011bn\u00ed \u201e\u00fasp\u011b\u0161nou\u201c tepelnou kontrolu v \u201ene\u00fasp\u011b\u0161nou\u201c.<\/p>\n

Spr\u00e1vn\u00fd p\u0159\u00edstup:<\/strong> P\u0159ed porovn\u00e1n\u00edm se skute\u010dn\u00fdm vstupn\u00edm v\u00fdkonem v\u017edy pou\u017eijte korek\u010dn\u00ed faktor teploty okol\u00ed na P_th. Pou\u017eijte nejteplej\u0161\u00ed o\u010dek\u00e1vanou teplotu okol\u00ed pro dan\u00e9 m\u00edsto instalace.<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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\u010casto kladen\u00e9 ot\u00e1zky \u2013 V\u00fdpo\u010dty to\u010div\u00e9ho momentu a p\u0159evodov\u00e9ho pom\u011bru \u0161nekov\u00e9ho reduktoru<\/h2>\n
\nJak moc z\u00e1le\u017e\u00ed na tom, kdy\u017e p\u0159esn\u00fd vypo\u010d\u00edtan\u00fd pom\u011br (nap\u0159. 47,2:1) neodpov\u00edd\u00e1 standardn\u00edmu pom\u011bru (50:1)?<\/summary>\n
Standardn\u00ed p\u0159evodov\u00e9 pom\u011bry \u0161nekov\u00fdch reduktor\u016f jsou nomin\u00e1ln\u011b ud\u00e1van\u00e9 hodnoty s toleranc\u00ed p\u0159ibli\u017en\u011b \u00b13%. \u0160nekov\u00fd reduktor tedy m\u016f\u017ee v praxi ve skute\u010dnosti dod\u00e1vat p\u0159evodov\u00e9 pom\u011bry 48,5:1 a\u017e 51,5:1, v z\u00e1vislosti na skute\u010dn\u00e9m po\u010dtu zub\u016f konkr\u00e9tn\u00ed jednotky. Pokud je v\u00e1\u0161 vypo\u010d\u00edtan\u00fd po\u017eadovan\u00fd p\u0159evodov\u00fd pom\u011br 47,2:1, v\u00fdb\u011br jednotky 50:1 v\u00e1m poskytne ni\u017e\u0161\u00ed v\u00fdstupn\u00ed ot\u00e1\u010dky, ne\u017e jsou vypo\u010d\u00edtan\u00e9 \u2013 ve v\u011bt\u0161in\u011b aplikac\u00ed dopravn\u00edk\u016f a m\u00edchadel je to p\u0159ijateln\u00e9. Pokud jsou v\u00fdstupn\u00ed ot\u00e1\u010dky p\u0159esn\u011b \u0159\u00edzeny (nap\u0159. synchroniza\u010dn\u00edm pohonem), pou\u017eijte k \u00faprav\u011b ot\u00e1\u010dek motoru frekven\u010dn\u00ed m\u011bni\u010d, abyste kompenzovali odchylku p\u0159evodu. Nikdy nevolte p\u0159evod ni\u017e\u0161\u00ed ne\u017e vypo\u010d\u00edtan\u00e1 hodnota \u2013 jinak budete m\u00edt v\u00fdstupn\u00ed ot\u00e1\u010dky vy\u0161\u0161\u00ed, ne\u017e jsou specifikovan\u00e9.<\/div>\n<\/details>\n
\nJak vypo\u010d\u00edt\u00e1m skute\u010dn\u00fd v\u00fdstupn\u00ed to\u010div\u00fd moment z \u00fadaj\u016f na typov\u00e9m \u0161t\u00edtku motoru?<\/summary>\n
Z typov\u00e9ho \u0161t\u00edtku motoru: T_motoru (N\u00b7m) = (P_typov\u00fd \u0161t\u00edtek \u00d7 9 550) \/ n_motoru. Motor o v\u00fdkonu 1,5 kW p\u0159i 1 450 ot\/min vytv\u00e1\u0159\u00ed na h\u0159\u00eddeli motoru T_motoru = (1,5 \u00d7 9 550) \/ 1 450 = 9,88 N\u00b7m. Toto je v\u0161ak jmenovit\u00fd trval\u00fd to\u010div\u00fd moment motoru \u2013 skute\u010dn\u00fd dod\u00e1van\u00fd to\u010div\u00fd moment z\u00e1vis\u00ed na mechanick\u00e9m zat\u00ed\u017een\u00ed. Pokud zat\u00ed\u017een\u00ed vy\u017eaduje pouze 50% kapacity motoru, motor dod\u00e1v\u00e1 4,94 N\u00b7m. Pro dimenzov\u00e1n\u00ed \u0161nekov\u00e9ho reduktoru v\u017edy vypo\u010d\u00edtejte po\u017eadovan\u00fd to\u010div\u00fd moment ze zat\u00ed\u017een\u00ed (s\u00edla zat\u00ed\u017een\u00ed \u00d7 rameno momentu) a pot\u00e9 dimenzujte motor na z\u00e1klad\u011b tohoto po\u017eadavku \u2013 ne naopak.<\/div>\n<\/details>\n
\nJak se p\u0159i pou\u017eit\u00ed frekven\u010dn\u00edho m\u011bni\u010de (VFD) zm\u011bn\u00ed v\u00fdpo\u010det to\u010div\u00e9ho momentu a p\u0159evodov\u00e9ho pom\u011bru?<\/summary>\n
M\u011bni\u010d s frekven\u010dn\u00edm m\u011bni\u010dem (VFD) m\u011bn\u00ed ot\u00e1\u010dky motoru, ale nikoliv to\u010div\u00fd moment motoru p\u0159i dan\u00e9 frekvenci. V\u00fdb\u011br \u0161nekov\u00e9ho reduktoru se st\u00e1le \u0159\u00edd\u00ed stejn\u00fdmi \u010dty\u0159mi vzorci \u2013 v\u00fdpo\u010det z to\u010div\u00e9ho momentu z\u00e1t\u011b\u017ee a po\u017eadovan\u00fdch v\u00fdstupn\u00edch ot\u00e1\u010dek, ur\u010den\u00ed p\u0159evodu z v\u00fdstupn\u00edch ot\u00e1\u010dek a maxim\u00e1ln\u00edch ot\u00e1\u010dek motoru. M\u011bni\u010d s frekven\u010dn\u00edm m\u011bni\u010dem (VFD) pak umo\u017e\u0148uje m\u011bnit ot\u00e1\u010dky motoru v r\u00e1mci p\u0159evodu, co\u017e zaji\u0161\u0165uje jemnou regulaci ot\u00e1\u010dek. D\u016fle\u017eit\u00e9 omezen\u00ed: p\u0159i frekvenc\u00edch VFD pod 30 Hz je \u00fa\u010dinnost chladic\u00edho ventil\u00e1toru motoru u standardn\u00edch asynchronn\u00edch motor\u016f sn\u00ed\u017eena (ventil\u00e1tor je namontov\u00e1n na h\u0159\u00eddeli). P\u0159i sn\u00ed\u017een\u00fdch ot\u00e1\u010dk\u00e1ch m\u016f\u017ee b\u00fdt nutn\u00e9 sn\u00ed\u017eit v\u00fdkon motoru nebo pou\u017e\u00edt samostatn\u011b nap\u00e1jen\u00fd chladic\u00ed ventil\u00e1tor. Tak\u00e9 p\u0159i velmi n\u00edzk\u00e9 frekvenci VFD (pod 10 Hz) nemus\u00ed b\u00fdt mazivo \u0161nekov\u00e9ho reduktoru dostate\u010dn\u011b prom\u00edch\u00e1v\u00e1no \u2013 ov\u011b\u0159te si minim\u00e1ln\u00ed doporu\u010den\u00e9 ot\u00e1\u010dky vstupn\u00edho h\u0159\u00eddele u dodavatele \u0161nekov\u00e9ho reduktoru.<\/div>\n<\/details>\n
\nJak se vypo\u010d\u00edt\u00e1 celkov\u00e1 \u00fa\u010dinnost dvoustup\u0148ov\u00e9ho \u0161nekov\u00e9ho reduktoru?<\/summary>\n
Pro dva stupn\u011b \u0161nekov\u00e9ho reduktoru zapojen\u00e9 v s\u00e9rii je celkov\u00e1 \u00fa\u010dinnost sou\u010dinem \u00fa\u010dinnost\u00ed jednotliv\u00fdch stup\u0148\u016f: \u03b7_total = \u03b7_stage1 \u00d7 \u03b7_stage2. Dva stupn\u011b s \u03b7 = 0,65 produkuj\u00ed \u03b7_total = 0,65 \u00d7 0,65 = 0,42 \u2013 celkov\u00e1 \u00fa\u010dinnost pouze 42%. Proto se dvoustup\u0148ov\u00e1 \u0161nekov\u00e1 uspo\u0159\u00e1d\u00e1n\u00ed pou\u017e\u00edvaj\u00ed pouze tehdy, kdy\u017e \u017e\u00e1dn\u00fd jednostup\u0148ov\u00fd \u0161nekov\u00fd reduktor nem\u016f\u017ee poskytnout po\u017eadovan\u00fd p\u0159evodov\u00fd pom\u011br (nad 100:1), a i tehdy m\u016f\u017ee b\u00fdt jeden \u0161nekov\u00fd stupe\u0148 v kombinaci s rovnob\u011b\u017en\u00fdm h\u0159\u00eddelem a spir\u00e1lov\u00fdm stupn\u011bm \u00fa\u010dinn\u011bj\u0161\u00ed alternativou. Kontakt Korea Ever-Power<\/a> pro veden\u00ed v\u00edcestup\u0148ov\u00e9ho uspo\u0159\u00e1d\u00e1n\u00ed pohonu.<\/div>\n<\/details>\n
\nPokud se skute\u010dn\u00e9 zat\u00ed\u017een\u00ed uk\u00e1\u017ee b\u00fdt v\u011bt\u0161\u00ed ne\u017e vypo\u010d\u00edtan\u00e9, sel\u017ee \u0161nekov\u00fd reduktor okam\u017eit\u011b?<\/summary>\n
Ne okam\u017eit\u011b a ne p\u0159edv\u00eddateln\u011b. \u0160nekov\u00fd reduktor pracuj\u00edc\u00ed nad svou T\u2082n se nezlom\u00ed p\u0159i prvn\u00edm cyklu p\u0159et\u00ed\u017een\u00ed \u2013 katalogov\u00e9 \u00fadaje zahrnuj\u00ed bezpe\u010dnostn\u00ed rezervu a bronzov\u00e9 kolo se p\u0159ed prasknut\u00edm plasticky podd\u00e1. Postupem \u010dasu se stane zrychlen\u00e9 opot\u0159eben\u00ed: povrch bronzov\u00e9ho kola p\u0159ekro\u010d\u00ed Hertz\u016fv bod n\u00e1vrhov\u00e9ho kontaktn\u00edho nap\u011bt\u00ed, za\u010dne se mikrokoroze, povrchov\u00fd materi\u00e1l se odstra\u0148uje rychleji, ne\u017e je navr\u017eeno, a nakonec se tlou\u0161\u0165ka zubu zmen\u0161\u00ed do bodu, kdy jednotka ztr\u00e1c\u00ed to\u010div\u00fd moment. Tento proces m\u016f\u017ee trvat m\u011bs\u00edce nebo roky v z\u00e1vislosti na tom, jak v\u00fdrazn\u011b zat\u00ed\u017een\u00ed p\u0159ekro\u010d\u00ed T\u2082n. Porucha nen\u00ed dramatick\u00e1 \u2013 jde o postupn\u00e9 zvy\u0161ov\u00e1n\u00ed v\u016fle a hluku, po kter\u00e9m nakonec n\u00e1sleduje ud\u00e1lost omezuj\u00edc\u00ed to\u010div\u00fd moment. Pokud m\u00e1te podez\u0159en\u00ed, \u017ee v\u00e1\u0161 st\u00e1vaj\u00edc\u00ed \u0161nekov\u00fd reduktor je p\u0159et\u00ed\u017een\u00fd, zm\u011b\u0159te teplotu sk\u0159\u00edn\u011b a p\u0159i p\u0159\u00ed\u0161t\u00ed v\u00fdm\u011bn\u011b oleje zkontrolujte obsah m\u011bdi v oleji \u2013 oboj\u00ed jsou v\u010dasn\u00e9 ukazatele p\u0159edt\u00edm, ne\u017e dojde k mechanick\u00e9mu selh\u00e1n\u00ed.<\/div>\n<\/details>\n
\nPokud vypo\u010d\u00edtan\u00e1 hodnota T_required spad\u00e1 mezi dv\u011b katalogov\u00e9 velikosti, m\u00e1m v\u017edy vybrat v\u011bt\u0161\u00ed?<\/summary>\n
Ano, v\u017edy zvolte v\u011bt\u0161\u00ed model, pokud po\u017eadovan\u00fd to\u010div\u00fd moment spad\u00e1 mezi dv\u011b standardn\u00ed velikosti \u0161nekov\u00fdch reduktor\u016f. Men\u0161\u00ed jednotka by pracovala bl\u00edzko sv\u00e9 konstruk\u010dn\u00ed hranice, tak\u017ee by nez\u016fst\u00e1val prostor pro kol\u00eds\u00e1n\u00ed zat\u00ed\u017een\u00ed, zm\u011bny okoln\u00ed teploty, kol\u00eds\u00e1n\u00ed viskozity oleje ani v\u00fdrobn\u00ed tolerance v poh\u00e1n\u011bn\u00e9m za\u0159\u00edzen\u00ed. Rozd\u00edl v n\u00e1kladech mezi sousedn\u00edmi velikostmi r\u00e1m\u016f u \u0161nekov\u00fdch reduktor\u016f je obvykle mal\u00fd \u2013 mnohem men\u0161\u00ed ne\u017e n\u00e1klady na p\u0159ed\u010dasnou poruchu a nepl\u00e1novanou v\u00fdm\u011bnu. Jedinou situac\u00ed, kdy je v\u00fdb\u011br men\u0161\u00ed jednotky opr\u00e1vn\u011bn\u00fd, je situace, kdy vypo\u010d\u00edtan\u00e1 hodnota T_required v\u00fdrazn\u011b podhodnocuje skute\u010dn\u00e9 zat\u00ed\u017een\u00ed a m\u00e1te v \u00famyslu v\u00fdpo\u010det p\u0159epracovat \u2013 v takov\u00e9m p\u0159\u00edpad\u011b za\u010dn\u011bte nejprve s p\u0159esn\u011bj\u0161\u00edm m\u011b\u0159en\u00edm zat\u00ed\u017een\u00ed. Prohl\u00e9dn\u011bte si na\u0161e rozsah \u0161nekov\u00fdch reduktor\u016f<\/a> porovnat velikosti sousedn\u00edch r\u00e1m\u016f.<\/div>\n<\/details>\n<\/div>\n

<\/p>\n

\n

V\u00fdb\u011br a v\u00fdpo\u010dtov\u00e1 podpora \u0161nekov\u00e9ho p\u0159evodu<\/h2>\n

Technick\u00fd t\u00fdm spole\u010dnosti Korea Ever-Power poskytuje ov\u011b\u0159en\u00ed v\u00fdb\u011bru \u0161nekov\u00e9ho p\u0159evodu pro specifick\u00e9 aplikace \u2013 v\u010detn\u011b kontroly v\u00fdpo\u010dtu kroutic\u00edho momentu, potvrzen\u00ed provozn\u00edho faktoru a posouzen\u00ed tepeln\u00e9ho v\u00fdkonu pro va\u0161e skute\u010dn\u00e9 okoln\u00ed a provozn\u00ed podm\u00ednky. Sd\u00edlejte parametry va\u0161\u00ed aplikace a my v\u00e1m vr\u00e1t\u00edme kompletn\u00ed doporu\u010den\u00ed pro v\u00fdb\u011br.<\/p>\n

Proch\u00e1zet \u0161nekov\u00e9 reduktory<\/a>
\nZa\u0161lete n\u00e1m sv\u00e9 \u00fadaje z aplikace<\/a><\/div>\n<\/div>\n<\/div>\n

St\u0159iha\u010d: Cxm<\/p>","protected":false},"excerpt":{"rendered":"

Worm Gear Reducer Torque and Ratio: The Calculation Guide Supplier recommendation tables are built around the average application. Your application has its specific load, duty cycle, ambient temperature, and shock character. This guide walks through the four core formulas and three worked examples so you can verify any worm gear reducer selection in under 20 […]<\/p>","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_et_pb_use_builder":"","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"categories":[1517],"tags":[218,363,365],"class_list":["post-1941","post","type-post","status-publish","format-standard","hentry","category-worm-gear-reducer","tag-worm-gear-reducer","tag-worm-gearbox","tag-worm-reducer-gearbox"],"_links":{"self":[{"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/posts\/1941","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/comments?post=1941"}],"version-history":[{"count":2,"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/posts\/1941\/revisions"}],"predecessor-version":[{"id":1943,"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/posts\/1941\/revisions\/1943"}],"wp:attachment":[{"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/media?parent=1941"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/categories?post=1941"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/worm-reducers.xyz\/cs\/wp-json\/wp\/v2\/tags?post=1941"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}